The answer is B because the formula would be 850+(415*24) and the sum of that would be 10810.
Answer:
The height of the pole is 167 m
Step-by-step explanation:
The given parameters are;
Increase in the length of the shadow = 90 m
Initial angle of elevation of the Sun = 58°
Final angle of elevation of the Sun = 36°
We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase in the length of the shadow
We have by sin rule;
90/(sin (22°) = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)
Let the initial ray from the top of the pole to the end of the shadow's length = l₁
90/(sin (22°) = l₁/(sin(122°)
l₁ = 90/(sin (22°) ×(sin(122°) = 283.3 m
Therefore;
The height of the pole = 283.3 m × sin(36°) = 166.52 m
The height of the pole= 167 m to three significant figures.
Answer:
- x(x - 2)(x + 5)
- x = 0, x = 2, x = -5
Step-by-step explanation:
x^3 + 3x^2 - 10x
~Factor
x(x - 2)(x + 5)
Solve for the zero.
x(x - 2)(x + 5) = 0
We know that; x = 0, x - 2 = 0, and x + 5 = 0
x = 0
x - 2 = 0
x = 2
x + 5 = 0
x = -5
Best of Luck!
1. Use a straightedge to draw line m and label a point on the line as point F
2. Construct a line perpendicular to line m through point F. Label a point on this line as point G.
3. With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
4. Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK.
5. Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.
6. Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.