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hichkok12 [17]
3 years ago
10

Simplify the Ratio 250: 550

Mathematics
2 answers:
pantera1 [17]3 years ago
3 0
The answer is 11:5 ……………….
erastovalidia [21]3 years ago
3 0
Answer 11:5
......................
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I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb
777dan777 [17]
The answer is 758 if I'm not mistaken
4 0
3 years ago
drawbridge at the entrance to an ancient castle is raised and lowered by a pair of chains. The figure represents the drawbridge
jasenka [17]

Answer:

4.0 meters, ∠C = 39°, ∠A = 51°

Step-by-step explanation:

Firstly, our diagram shows us that the given triangle is actually a right triangle. So we can use the <em>Pythagorean Theorem</em> to solve for the height of the chain:

a^{2} +b^{2} =c^{2}

(3.3)^{2} +b^{2} =(5.2)^{2}

b^{2} =(5.2)^{2}-(3.3)^{2}

b =\sqrt{(5.2)^{2}-(3.3)^{2}}

b=4.0187...

b=4.0 m

Now, we can use the <em>Law of Cosines</em> to figure out one of the acute angles:

c^{2}  =a^{2} +b^{2} -2ab(cos(C))

(3.3)^{2}  =(4.0)^{2} +(5.2)^{2} -2(4.0)(5.2)(cos(C))

cos(C)=\frac{(3.3)^{2}-(4.0)^{2} -(5.2)^{2}}{-2(4.0)(5.2)}

C=cos^{-1}( \frac{(3.3)^{2}-(4.0)^{2} -(5.2)^{2}}{-2(4.0)(5.2)})

C=39.3915...

∠C = 39°

And since we know that all angles in a triangle add up to 180°:

∠A + ∠B + ∠C = 180

∠A + 90 + 39 = 180

∠A = 180 - 90 - 39

∠A = 51°

However, you should always review any answers on the Internet and make sure they are correct! Check my work to see if I made any mistakes!

7 0
3 years ago
The sum of what integer and 181 is equal to -236?
slavikrds [6]

Answer:

<h2>- 417</h2>

Step-by-step explanation:

n - integer

The sum of n and 181 is equal to -236:

n + 181 = -236              <em>subtract 181 from both sides</em>

n + 181 - 181 = -236 - 181

n = -417

6 0
3 years ago
Can I get steps on how to solve this?
LUCKY_DIMON [66]

Answer:divided the total buy 9 and if I’m reading correctly the total is two

Step-by-step explanation:

6 0
2 years ago
11. 1Owl0 – 19w" + 6W8
Gennadij [26K]
I’m so confused what are u trying to ask
5 0
3 years ago
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