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AfilCa [17]
3 years ago
10

2.5 pounds of grapes cost $2.25 what is the cost per pound

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
7 0

Answer:

$0.9 per pound

Step-by-step explanation:

$2.25 divided by 2.5

divide the cost of the item by its weight in pounds

Sergeeva-Olga [200]3 years ago
3 0

Answer:

$0.9 per pound

Step-by-step explanation:

$2.25 divided by 2.5

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Priyanka and Ethan were asked to find an explicit formula for the sequence -3,-14,-25,-36,...
irga5000 [103]

Answer:

a_{n} = 8 - 11n

Step-by-step explanation:

These are the terms of an arithmetic sequence with n th term

a_{n} = a + (n - 1)d

where a is the first term and d the common difference

here a = - 3 and

d = - 14 - (- 3) = - 14 + 3 = -11, thus

a_{n} = - 3 - 11(n - 1)

                        = - 3 - 11n + 11

                        = 8 - 11n

3 0
3 years ago
A 12 pack of diet soda has dimensions 4.75in and 28.5in whats the volume of the 12 pack round to the nearest ten
ExtremeBDS [4]

Answer:

Volume = 643.0\ in^3

Step-by-step explanation:

Given

Dimension: 4.75in, 4.75in and 28.5in

<em>[The complete dimension is missing from the question]</em>

Required

Calculate the volume

The volume is calculated as thus:

Volume = 4.75in * 4.75in * 28.5in

Volume = 643.03125in^3

Volume = 643.0\ in^3 --- approximated

6 0
3 years ago
A box with a square base and open top must have a volume of 296352 c m 3 . We wish to find the dimensions of the box that minimi
mestny [16]

Answer:

  • Base Length of 84cm
  • Height of 42 cm.

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 296352 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume, V=x^2h=296352

h=\dfrac{296352}{x^2}

Surface Area of the box = Base Area + Area of 4 sides

A(x,h)=x^2+4xh\\$Substitute h=\dfrac{296352}{x^2}\\A(x)=x^2+4x\left(\dfrac{296352}{x^2}\right)\\A(x)=\dfrac{x^3+1185408}{x}

Step 2: Find the derivative of A(x)

If\:A(x)=\dfrac{x^3+1185408}{x}\\A'(x)=\dfrac{2x^3-1185408}{x^2}

Step 3: Set A'(x)=0 and solve for x

A'(x)=\dfrac{2x^3-1185408}{x^2}=0\\2x^3-1185408=0\\2x^3=1185408\\$Divide both sides by 2\\x^3=592704\\$Take the cube root of both sides\\x=\sqrt[3]{592704}\\x=84

Step 4: Verify that x=84 is a minimum value

We use the second derivative test

A''(x)=\dfrac{2x^3+2370816}{x^3}\\$When x=84$\\A''(x)=6

Since the second derivative is positive at x=84, then it is a minimum point.

Recall:

h=\dfrac{296352}{x^2}=\dfrac{296352}{84^2}=42

Therefore, the dimensions that minimizes the box surface area are:

  • Base Length of 84cm
  • Height of 42 cm.
5 0
3 years ago
When you solve an equation, you must
MAXImum [283]

Answer:

x is equal to 6

Step-by-step explanation:

4x=24

divide both sides by 4

4 eliminates 4 leaving x behind

4 divides 24 making x =6

3 0
4 years ago
Ernest wants to buy 21 new books for his book collection. If the average price for a
lukranit [14]

Answer:

If each book cost $20.45 then you times it by 21 and the answer you would get is 429.45

Step-by-step explanation:

im 99% that its correct

3 0
2 years ago
Read 2 more answers
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