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3 years ago

Helppp please??? ill give most brainly

Mathematics

2 answers:

kykrilka [37]3 years ago

6 0

I believe the answer is 46!!

Sergeeva-Olga [200]3 years ago

5 0

Answer:

Step-by-step explanation:

Since B is the midpoint of AC, the segments AB and BC must have equal length. This means that x + 13 = 2x + 3. Solving this, we see that x = 10. By substituting 10 for x, we see that the length of AB is 23, so the length of AC is 2*23, which is 46.

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If the volume of a sphere is equal to the volume of a cube, what is the ratio of the edge of the cube to the radius of the spher

Pachacha [2.7K]

Answer: The answer is (C) 1.61.

Step-by-step explanation: Given that the volume of a sphere is equal to the volume of a cube. We are to find the ratio of the edge of the cube to the radius of the sphere.

Let, 'r' be the radius of the sphere and 'e' be the edge of the cube. Then, the volume of the sphere is given by

$V_s=\dfrac{4}{3}\pi r^3,$

and the volume of the cube is

$V_c=e^3.$

According to the question, we have

$V_s=V_e\\\\\Rightarrow \dfrac{4}{3}\pi r^3=e^3\\\\\\\Rightarrow \dfrac{4}{3}\times\dfrac{22}{7}r^3=e^3\\\\\\\Rightarrow 88r^3=21e^3\\\\\Rightarrow 4.44r=2.75e\\\\\Rightarrow \dfrac{e}{r}=\dfrac{4.44}{2.75}\\\\\Rightarrow e:r=1.61.$

Thus, the correct option is (C) 1.61.

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3 years ago

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Georgia [21]

Answer:

(3,-4)

Step-by-step explanation:

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3 years ago

identify the kind of sample that is described. the superintendent of a large school district wants to test the effectiveness of

Andrei [34K]

The sample used in this problem is classified as cluster.

<h3>How are samples classified?</h3>

Samples may be classified as:

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Stratified: Also divides the population into groups. Then, a equal proportion of each group is surveyed.

For this problem, a group of schools is selected, and then the new program is applied to all students in these school, meaning that all elements in the cluster are surveyed, so cluster sampling is used.

More can be learned about classification of samples at brainly.com/question/25122507

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Step-by-step explanation:

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