Answer:
<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>
By De morgan's law
which is Bonferroni’s inequality
<h3>Result 1: P (Ac) = 1 − P(A)</h3>
Proof
If S is universal set then
<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>
Proof:
If S is a universal set then:
Which show A∪B can be expressed as union of two disjoint sets.
If A and (B∩Ac) are two disjoint sets then
B can be expressed as:
If B is intersection of two disjoint sets then
Then (1) becomes
<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>
Proof:
If A and B are two disjoint sets then
<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>
Proof:
If B is subset of A then all elements of B lie in A so A ∩ B =B
where A and A ∩ Bc are disjoint.
From axiom P(E)≥0
Therefore,
P(A)≥P(B)
Answer:
a. We can tell that Maurice divided incorrectly because if the dividend is 62, you can't have a remainder of 87, because 62 goes into 87 once, so the answer would be 17 with a remainder of 25. B. YOu can use that fact to find the correct quotient, because 87/62 is 1, with a remainder of 25, so 16+1=17, so the answer is 17 with a remainder of 25. Please vote the brainliest.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
Required
Order from least to greatest
Comparing 16390, 16550 and 16237.
The order of arrangement from least to greatest is:
16327, 16390 and 16550.
So, we have:
