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Eddi Din [679]
2 years ago
5

What is the exact volume of the cylinder? 32π in³ 64π in³ 128π in³ 512π in³ Cylinder with radius labeled 4 inches and height lab

eled 8 inches
Mathematics
2 answers:
8_murik_8 [283]2 years ago
6 0
The answer is 128 pi in^3. You have to multiply 4x4, then multiply that by 8 to get 128.
mart [117]2 years ago
5 0

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

where

r is the radius of the base of the cylinder

h is the height of the cylinder

In this problem we have

r=4\ in\\h=8\ in

substitute the values in the formula

V=\pi 4^{2} 8=128 \pi\ in^{3}

therefore

<u>the answer is the option </u>

128 \pi\ in^{3}

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A team of bakers can roll and form 5 dozen pretzels in 9 minutes. How many pretzels can this team form in 1 hour?
vodka [1.7K]

Answer 400


Step-by-step explanation: 1 hours = 60 min

60 min divided by 9 = 6.66666667

6.66666667 * 5 dozen pretzels/ 60 pretzel = 400

did it pretty quickly may be wrong


5 0
3 years ago
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Which equation represents the partial sum of the geometric series?
user100 [1]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
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which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater
Nutka1998 [239]

Answer:

\frac{\sqrt[3]{16y^4}}{x^2}

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices \sqrt[n]{a}  = a^{\frac{1}{n}}

So,

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} } gives

\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}

Also from laws of indices

(ab)^n = a^nb^n

So, the above expression can be further simplified to

\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}

Multiply the exponents gives

\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

Substitute 2^5 for 32

\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

From laws of indices

\frac{a^m}{a^n} = a^{m-n}

This law can be applied to the expression above;

\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})} becomes

2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}

Solve exponents

2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}

2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}

From laws of indices,

a^{-n} = \frac{1}{a^n}; So,

2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}} gives

\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}

The expression at the numerator can be combined to give

\frac{(2y)^{\frac{4}{3}}}{x^2}

Lastly, From laws of indices,

a^{\frac{m}{n} = \sqrt[n]{a^m}; So,

\frac{(2y)^{\frac{4}{3}}}{x^2} becomes

\frac{\sqrt[3]{(2y)}^{4}}{x^2}

\frac{\sqrt[3]{16y^4}}{x^2}

Hence,

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} } is equivalent to \frac{\sqrt[3]{16y^4}}{x^2}

8 0
3 years ago
How many anagrams are there to the word FRIDAY? In how many of these do the letters 'DAY' appear consecutively? (Disregard wheth
QveST [7]

There are 720 total different combinations, and 24 of those will have the letters DAY consecutively within all those combinations.

<u>Explanation:</u>

FRIDAY is a six letter word.

To form all combinations of letters, we would have six choices of letters to fill the first spot. Whatever letter you choose for the first spot, you then have five choices of letters to fill the second spot. Four choices of letters to fill the third spot. And so on.

So, the total number of different combinations of the six letters would be 6!

6! = 6 X 5 X 4 X 3 X 2 X 1

   = 720

DAY could appear consecutively starting in 4 different spots: the 1st, 2nd, 3rd, and 4th spots of all combinations. DAY will appear consecutively 6 times in each of those 4 starting spots.

6 X 4 = 24.

So, there are 720 total different combinations, and 24 of those will have the letters DAY consecutively within all those combinations.

7 0
3 years ago
CAN SOMEONE HELP ME FIND THE CIRCUMFERENCE
aleksandrvk [35]
Tbh idk all I got was 51.496 I’m dumb i just want points ^_^
7 0
3 years ago
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