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2 years ago

5

What is the exact volume of the cylinder? 32π in³ 64π in³ 128π in³ 512π in³ Cylinder with radius labeled 4 inches and height lab

eled 8 inches

2 answers:

8_murik_8 [283]2 years ago

6 0

The answer is 128 pi in^3. You have to multiply 4x4, then multiply that by 8 to get 128.

mart [117]2 years ago

5 0

we know that

The volume of a cylinder is equal to

$V=\pi r^{2} h$

where

r is the radius of the base of the cylinder

h is the height of the cylinder

In this problem we have

$r=4\ in\\h=8\ in$

substitute the values in the formula

$V=\pi 4^{2} 8=128 \pi\ in^{3}$

therefore

<u>the answer is the option </u>

$128 \pi\ in^{3}$

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I need some help with this

ale4655 [162]

Answer:

You forgot to say how many miles she drove

Step-by-step explanation:

4 0

2 years ago

A number, X, rounded to 1 decimal place is 3,7<br> Write down the error interval for x,

sp2606 [1]

Answer:

The error interval for x is:

[3.65,3.74]

Step-by-step explanation:

The number after rounding off is obtained as:

3.7

We know that any of the number below on rounding off the number to the first decimal place will result in 3.7:

3.65 3.66 3.67 3.68 3.69 3.70 3.71 3.72 3.73 3.74

( Because if we have to round off a number present in decimals to n place then if there is a number greater than or equal to 5 at n+1 place then it will result to the one higher digit at nth place on rounding off and won't change the digit if it less than 5 )

Hence, the error interval is:

[3.65,3.74]

6 0

2 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial:

$\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3$

$\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4$

8 0

2 years ago

Sorry I suck at math do u get this one

maks197457 [2]

Answer:

Number one will be 11 minutes

Number two will be 525 words

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Which describes the solution of the inequality y > −15? Select all the points that are part of the solution.

Svetllana [295]

Step-by-step explanation:

y > -15

y is bigger than -15

= -14 , -13 , -12 , -11 , -10 , etc . . .

8 0

2 years ago