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3 years ago

The sum of 3 consecutive odd numbers is 183. What is the third number in this sequence?

Mathematics

2 answers:

Gekata [30.6K]3 years ago

7 0

Answer:

The third number in this sequence is 63.

Step-by-step explanation:

Let the first odd number be x.

Since our sequence are consecutive odd numbers, the second term must be (x + 2) and the third (x + 4). If we only add one, we will get even numbers.

Their sum is 183. Hence:

$x+(x+2)+(x+4)=183$

Solve for x. Combine like terms:

$3x+6=183$

Subtract six from both sides:

$3x=177$

And divide both sides by three. Hence:

$x=59$

Therefore, our sequence is 59, 61, and 63.

The third number in this sequence is 63.

Note: If we do not get an odd number or if we get a fraction for x, we can conclude that no three consecutive integers sum to 183.

natta225 [31]3 years ago

3 0

Answer:

Step-by-step explanation:

3x + 6 = 183

3x = 177

x = 59

(x+2) = (59+2) = 61

It is correct on khan academy

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$\large\begin{array}{l} \textsf{Both 
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\begin{array}{rcl} \mathsf{tan\,x=-3.4}&~\textsf{ or 
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$\large\textsf{I hope it helps.}$

Tags: trigonometric trig quadratic equation tangent tan solve inverse symmetry parity odd function

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