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ololo11 [35]
3 years ago
16

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−1, −1)?

Mathematics
1 answer:
777dan777 [17]3 years ago
4 0
First find the slope of this new line; it's the same as the slope of the "given line," which you unfortunately have not yet given.  Let's call that slope "m."

Then, the equation in point-slope form of the new line is

y - (-1) = m(x - [-1]), or    y+1 = m(x+1)

Please go back to the original question, obtain the slope of the "given line," and substitute that value for m in y+1 = m(x+1).
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I’ve Tried solving this and i just can’t get it , 64 = 4 + 12g
Alika [10]

Answer:

5

Step-by-step explanation:

64 = 4 + 12g

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8 0
2 years ago
Please help me. This is real confusing. ​
katrin2010 [14]

Answer:

1st problem: b) A=2500(1.01)^{12t}

2nd problem:  c) A=2500e^{.12t}

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

A=P(1+\frac{r}{n})^{nt}

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

A=2500(1+\frac{.12}{12})^{12t}

Time to clean up the inside of the ( ).

A=2500(1+.01)^{12t}

A=2500(1.01)^{12t}

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

A=Pe^{rt}

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

A=2500e^{.12t}.

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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