The answer is D. A turtle suns itself on a rock during a cool day
(Initial individuals + newborn individuals) - dead individuals = total individuals
Growth rate = (total individuals/initial individuals) * 100
Population growth rate = new percentage minus 100%
Calculations
(1000 + 500) - 200 = 1500 - 200 = 1300
Growth rate = (1300/ 1000) * 100
= 1.3 * 100
= 130%
Population growth rate = 130% - 100%
= 30% per year if it is uniform
Answer:
The fate of glucose-6-phosphate,glycolytic intermediates and pentose phosphate pathways are described below
Explanation:
Fate of Glucose -6-phosphate
Glucose-6-phosphate undergo dephosphorylation to form glucose when there is an increase demand of glucose in the body.
Glucose-6-phosphate enters into pentose phosphate pathway to synthesize ribose-5-phosphate which is used during denovo pathway of purine nucleotide biosynthesis.
Fate of glycolytic intermediates
Glyceraldehyde-3-phosphate is an important intermediate of glycolysis.The glyceraldehyde-3-phosphate act as a precursor during lipogenesis that deals with the biosynthesis of triacylglycerol.
Fate of pentose phosphate pathway intermediates
Ribose-5-phosphate and NADPH are the important intermediates of pentone phosphate pathway.
Ribose-5-phosphate act as a substrate molecule during the denovo biosynthesis pathway of purine nucleotides.
NADPH act as a reducing agent during fatty acid biosynthesis process.
