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kobusy [5.1K]
3 years ago
11

Someone help and makes sure the answer is right please :)

Mathematics
2 answers:
Gemiola [76]3 years ago
5 0

Answer:

6

Step-by-step explanation:

-4+14x=80

14x=84

x=6

Hopefully, it helps and it's correct!

oksian1 [2.3K]3 years ago
4 0

Answer:

x=6

Step-by-step explanation:

Since the two lines  are  parallel, the angles are congruent to each other.

-4+14x=80

14x=84

x=6

Hope  this helps!

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Find the least common denominator, which is 24.

4/24 - 3/24 = 1/24 
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The answer is A

Step-by-step explanation:

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3 years ago
The sum of two numbers is 12<br> and their product is 32.<br> What are the two numbers ?
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Answer:

8 and 4

Step-by-step explanation:

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8 0
3 years ago
Between the time Iko woke up and lunchtime,the temperature rose by 11.Then by the time he went to bed,the temperature dropped by
dimaraw [331]

Answer:

<u></u>

  • <u>11 + ( - 14)</u>

Explanation:

The complete question is:

<em>Between the time iko woke up and lunchtime, the temperature rose by 11º. Then by the time he went to bed, the temperature dropped by 14º.</em>

<em />

<em>Write an addition expression for the temperature relative to when iko woke up. </em>

<em />

<h2>Solution</h2>

It is said that between the time Iko woke up and lunchtime, the temperature rose by 11 degrees. A rise means the temperature increased and you must add 11º.

Then, relative to when Iko woke up the temperature is:

  • + 11º

Then, by the time Iko went to bed, the temperature dropped by 14º. A drop means that the change is negative. This means that you must add a negative number, and the additive expression is:

  • +  11º + (- 14º).

If you want the overall change in temperature you do the operation:

  • 11 + (-14) =  11 - 14 = - 3. A net decrease of 3º.

But the answer to this question is the additive expression:

  • 11 + ( - 14) ← answer
4 0
3 years ago
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
4 years ago
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