We have trapezoid with congruent legs.
30x + 11y = 2x + 3
28x +11y = 3
Also we have
30x + 11y = 12
We got 2 equations:
30x + 11y = 12
28x +11y = 3 (*-1) -----> -28x -11y = -3
30x + 11y = 12
<u> -28x -11y = -3</u>
2x = 9
x=9/2
30x + 11y = 12 ------> 30*9/2 +11y =12 ------> 135+11y =12, ---> 11y = - 123,
y= - 123/11
First, solve the area of the entire large rectangle (28)(45) = 1260
Next, find the area of the chunk that is cut out (11)(15) = 165
- we know the width is 15 because 45 - 6 - 24
Subtract the cut out piece from the overall rectangle 1260 - 165 = 1095
B. Right (they are 90° angles)
D. Adjacent (they share sides)
G. Supplementary (the total of the 2 angles is 180°)
Answer:
11
Step-by-step explanation:
1st plug in the given numbers for each variable (the letters)
4 x 6 ÷ 3 + 3 =
Next, use the order of operations to solve the expression.
4 x 6 ÷ 3 + 3 =
24 ÷ 3 + 3 =
8 + 3 = 11
