length = 3234 m and width = 1614 m
let the width = w then length = 2w + 6
Perimeter = 2 ( length + width )
= 2 (2w + 6 + w ) = 2 ( 3w + 6 ) = 6w + 12
given perimeter = 9696 the equating gives
6w + 12 = 9696
subtract 12 from both sides
6w = 9696 - 12 = 9684
divide both sides by 6
w = = 1614
width = 1614 m and length = (2 × 1614 ) + 6 = 3234 m
Each student pays 7.25 for lunch.
Multiply that by 25 for the total lunch cost: 25 * 7.25 = 181.25.
Subtract the lunch total from the total cost to find the total ticket amount:
443.75 - 181.25 = 262.50
Now divide total ticket amount by 25 students to find the cost of one ticket:
262.50 / 25 = $10.50
The first choice is the correct answer.
Answer:
1. b⁵
2. +16m⁹
Step-by-step explanation:
1. Add exponents: b³⁺² = b⁵
2. Negative and Negative = positive
2*8 = 16
m⁴⁺⁵ = m⁹
Hence: + 16m⁹
<span>x</span>²<span> - 5x + 6
x(x-3)-2(x-3)
Solution:
(x-2)(x-3)</span>
What the question here? If how many team are there it would go
118+121=9+10p
239=9+10p
Subtract 9 from both sides
230=10p
Divide by 10
23=p
Correct form
P=23