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PolarNik [594]
3 years ago
13

Holsen wants to know the theoretical and experimental probability of rolling a number larger than a 3 on a 6-sided number cube n

umbered 1 to 6. He rolls the number cube 6 times and records the results in this table.
4 1 3
3 5 2
Drag and drop the answers in the boxes to correctly complete the sentences comparing theoretical probability and experimental probability.

The theoretical probability of rolling a number larger than 3 is ________ because this is what ______. The experimental probability of rolling a number larger than 3 is _______ because this is what ______.
Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

The theoretical probability of rolling a number larger than 3 is 1/2 because this is what we expect to happen. The experimental probability of rolling a number larger than 3 is 1/3 because this is what actually happened.

Step-by-step explanation:

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The left side  0.25  does not equal to the right side  0.125  , which means that the given statement is false.

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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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3 years ago
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