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2 years ago

Submit your answers in simplest radical form. help :(

Mathematics

2 answers:

rusak2 [61]2 years ago

8 0

Answer:

x = 6√2, y = 6

Step-by-step explanation:

This is an isosceles triangle as one angle measures 45° and the other is a right angle, so it measures 90°.

Therefore, you know that y will equal 6.

You have to multiply a by √2 to find x.

6 x √2 = 6√2

Hope this helps!

Leokris [45]2 years ago

4 0

Answer:

x = 6 $\sqrt{2}$

y = 6

Step-by-step explanation:

in a 45-45-90 triangle the two legs are equal, so XY = YZ

also, the leg to hypotenuse ratio is 1 : $\sqrt{2}$

so x = 6 · $\sqrt{2}$

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Follow the order of operations to find the value of the expression 6+(9÷3)

Sliva [168]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

7) If £1 = €1.14. Work out what €144 is in pounds.

jonny [76]

Answer:

$126\frac{6}{19}$ £

Step-by-step explanation:

£1 = €1.14 / $*\frac{144}{1.14}$

£ $\frac{144}{1.14}$ =144€= $126\frac{6}{19} \\$ £

8 0

2 years ago

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

2 years ago

W* <img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D" id="TexFormula1" title="\frac{5}{6}" alt="\frac{5}{6}" align="absmid

evablogger [386]

Answer:

5/6 w

Step-by-step explanation:

reorder the terms ( use the commuative property)

5/6 w

so the answer is 5/6 w

7 0

3 years ago

A bag of candy contains 50 pieces of candy. The flavors are orange, strawberry, apple and

swat32

Answer:

Step-by-step explanation:

Let the probability of picking an orange = P(O), and the probability of picking a strawberry = P(S),

Based on the question, he picked an orange first and the probability of picking that is

P(O) = 12/50

Then he picked a strawberry on the second pick, the probability of picking the strawberry is P(S) and we'll find that later.

The probability of picking orange then strawberry with replacement is

P(O) × P(S) = 9/125

Substitute the P(O)=12/50,

12/50 × P(S) = 9/125

P(S) = 3/10

Then by finding the number of strawberry candies, we'll just have to multiply P(S) with the total number of candies, i.e.

Number of strawberry candy

= 3/10 × 50

= 15

8 0

2 years ago