Senior tickets (x)
Child tickets (y)
First day: 3x + 5y = 70
second day: 12x + 12y = 216
Solve the system of equations (use elimination)
Multiply first equation by -4 -4(3x + 5y = 70), which makes it
-12x - 20y = -280
(+)12x + 12y = 216 add to second equation
-8y = -64
divide by -8. y = 8
Plugin the y value to either equation ( I will choose first equation)
3x + 5(8) =70
3x+ 40 = 70
3x = 30
x = 10
Senior tickets are $10, child tickets are $8
Answer:
5qt 1pt
Step-by-step explanation:
It’s easy just do it
First find the the value of t where the curve intersects the Y-axis. This is when x = 0.
x = t^2 - 2t = 0 = t(t - 2)
So t= 0 and t = 2
dA = (0 - x)*dy .... Since the curve has negative x in this region
y = SQRT(t) and dy = [(1/2)/SQRT(t)]dt
dA = [2t - t^2][(1/2)/SQRT(t)]dt
dA = [t^(1/2) - (1/2)t^(3/2)]dt
Integrate to get: A = (2/3)t^(3/2) - (1/5)t^(5/2)
Now evaluate from t= 0 to t = 2.
Area = [(2/3)2^(3/2) - (1/5)2^(5/2)] - [0]
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Area = SQRT(2)[4/3 - 4/5]
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Area = SQRT(2)[8/15) = 0.754
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Answer:
1. The slope of the line is 7/3
2. y intercept is -3
3. y= 7/3x -3
Step-by-step explanation:
To find the slope of the line you use the equation y2-y1/x2-x1
y2 and y1 are y coordinates of the 2 coordinates on the same line that you want to find the slope of and the same with x2 and x1
The y-intercept is the point where the line crosses the y axis and x= 0
the equation of a line is y= mx+b
m= slope
b= y intercept
