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docker41 [41]
3 years ago
10

3/4 x 21 show your work

Mathematics
1 answer:
Mashcka [7]3 years ago
4 0
3/4 x 21 would be 15.75.
All you had to do was multiply 3/4 and 21.
Hope this helps.
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Suppose that 10 sophomores, 3 juniors, and 10 seniors are candidates for a prestigious mathematics award of which three will be
faltersainse [42]

Answer:

1771 possible ways

Step-by-step explanation:

In this case, we need to know first how many candidates are in total:

10 + 3 + 10 = 23 candidates in total.

Now, we need to choose 3 of them to receive an award. In this case, we have several scenarios, but as it's an award we can also assume that the order in which the candidates are chosen do not matter, so, the formula to use is the following:

C = m! / n! (m - n)!

Where m is the total candidates and n, is the number of candidates to be chosen. Replacing this data we have:

C = 23! / 3! (23 - 3)!

C = 2.59x10^22 / 6(2.43x10^18)

C = 1771

So we have 1771 ways of choose the candidates.

7 0
2 years ago
What is the constant term in the expression?<br> 15a + 10b + 5 – 7b
MA_775_DIABLO [31]

Answer:

5

Step-by-step explanation:

15a , 10b , and -7b are coefficients.

4 0
2 years ago
Find the missing probability.<br> P(A) = ?<br> P(B) = 2/5<br> P(A and B) = 6/25
Trava [24]

Answer:

3/5

Step-by-step explanation:

3/5 x 2/5 =  6/25

6 0
2 years ago
Which line plot displays a data set with an outlier?<br><br> Plz answer quickly!
iren2701 [21]
The answer is the first data set because remember, an outlier is a number in a data set that is extremely far away from all of the other numbers.

You can easily tell which one is the outlier, the first data set's outlier is 13, because it is was placed so far away from the other data points.

We know that the first data set is correct because all of the other data sets have numbers that are clustered together.

~Hope I helped!~
7 0
3 years ago
Ou pick a card at random. Without putting the first card back, you pick a second card at random.
Arte-miy333 [17]
If you cards are only 5,6,7, then the probability of getting even, then even would be zero.

The directions say that the card is not replaced. Therefore, once you pick the 6, there would be no more even cards.
5 0
3 years ago
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