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Romashka-Z-Leto [24]
3 years ago
11

2) Consider the quadratic sequence 72, 100, 120, 132

Mathematics
1 answer:
valina [46]3 years ago
3 0

9514 1404 393

Answer:

  Tn = -4n² +40n +36

Step-by-step explanation:

A graphing calculator readily performs the quadratic regression, yielding the formula ...

  Tn = -4n² +40n +36

__

The first and second differences of the given sequence terms are ...

  28, 20, 12 and -8, -8

The coefficient of the squared term is half the second difference, so is -4. Then the sequence of squared terms is -4n²:

  -4, -16, -36, -64

Subtracting these values from the original sequence gives the linear sequence ...

  76, 116, 156, 196

which has first term 76 and common difference 40. The equation for the n-th term of this is ...

  an = 76 +40(n -1) = 36 +40n

Adding this linear sequence to the sequence of squared terms, we get ...

  Tn = -4n² +40n +36

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8 0
4 years ago
In △QRS, QR ‖ TU. Given that TQ=6, ST=10, and UR=15, find SU.
tresset_1 [31]

Answer:

SU=25

Step-by-step explanation:

We can set up a ratio as STU and SQR are similar because of the SAS similarity theorem.

TQ:SQ

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Therefore the ratio of STU:SQR is 3:8

We can use this to find SU

UR:SR=3:8

15:SR=3:8

Cross multiply

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