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seropon [69]
3 years ago
11

Help me please !! The picture is attached

Mathematics
1 answer:
nydimaria [60]3 years ago
6 0

Answer:

  • x+3
  • 5

Step-by-step explanation:

On the interval [-3, -1), the function is a line with a slope of +1 and an x-intercept of -3. It can be described by ...

  f(x) = x +3

__

On the interval [-1, 1] the function is a constant. It can be described by ...

  f(x) = 5

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BlackZzzverrR [31]

Answer: (1) mean = 9.46; standard deviation = 3.74

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2 years ago
0.32 as a mixed number
torisob [31]

Answer:

Hi! The answer to your question is 0 8/25

Step-by-step explanation:

☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆

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2 years ago
A restaurant offers a combo special with 3 different sandwiches, 2 different salads, and 5 different drinks. From how many diffe
m_a_m_a [10]

Answer:

30 ways

Step-by-step explanation:

Given the following information:

  • 3 different sandwiches
  • 2 different salads
  • 5 different drinks

Let assume that the combo contains:  1 sandwich, 1 salad, and 1 drink

Hence, we have:

  • The total possible ways of choosing sandwiches she can choose is: 3
  • The total possible ways of choosing salads she can choose is: 2
  • The total possible ways of choosing drinks she can choose is: 5

=> Total ways = 3*5*2 = 30 ways or there are 30 different combos Keisha can choose

Hope it will find you well.

5 0
3 years ago
In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

Learn more about the Area of the triangle at

brainly.com/question/23945265

#SPJ4

6 0
2 years ago
A=1/3b then b=?a i really want the answer
scoray [572]

Answer:

b=3a

Step-by-step explanation:

1/3b times 3 = b

a times 3 = 3a

4 0
3 years ago
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