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-BARSIC- [3]
2 years ago
10

10. A company finds that 45% of first-time visitors to its website do not buy any of its products. If there are 75 first-time vi

sitors on a given day, what is the probability that exactly 36 of them buy a product? Round your answer to the nearest thousandth. Answer choices: 0.044 0.080 0.450 0.550
Mathematics
1 answer:
vekshin12 years ago
8 0

Using the binomial distribution, it is found that the probability that exactly 36 of them buy a product is of 0.044.

For each first-time visitor, there are only two possible outcomes, either they buy a product, or they do not. The probability of a first-time visitor buying a product is independent of any other first-time visitor, hence the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 45% of first-time visitors to its website do not buy any of its products, hence 55% buy, that is, p = 0.55.
  • There are 75 first-time visitors on a given day, hence n = 75.

The probability that exactly 36 of them buy a product is P(X = 36), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 36) = C_{75,36}.(0.55)^{36}.(0.45)^{39} = 0.044

More can be learned about the binomial distribution at brainly.com/question/24863377

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Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

6 0
3 years ago
Find the distance between two points (5,10) and (-4,6)​
Helga [31]

Answer:

Explanation:

The formula for calculating the distance between two points is:

d

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

Substituting the values from the points in the problem gives:

d

=

√

(

−

6

−

−

3

)

2

+

(

−

4

−

−

5

)

2

d

=

√

(

−

6

+

3

)

2

+

(

−

4

+

5

)

2

d = √ ( − 3 ) 2+ 1 2

d = √ 9+ 1

d = √ 10

Or

d = 3.162

rounded to the nearest thousandth

7 0
3 years ago
You are creating a logo for a local company in the shape of an isosceles triangle. The legs measure 5 inches each. What is the g
Bumek [7]

Answer:

9 inches

Step-by-step explanation:

Here, we want to know the greatest length of the third side

We apply the triangle inequality theorem here

To get the third side, then the sum of the lengths of the two must be greater than the measure of the third side

let us call the third side x

Then;

5 + 5 > x

10 > x

The highest whole number before 10 is 9: so it is the greatest possible whole number the base of the isosceles triangle can have

7 0
3 years ago
Forty-eight same-sized chips numbered from 1 to 48 are placed in a barrel. One chip is randomly pulled from the barrel.
Archy [21]
<span>probability that the number on the chip is greater than or equal to 11 
=
38/48 = 19/24</span>
4 0
3 years ago
Question Help
ValentinkaMS [17]

Step-by-step explanation:

We assume that the advertising rates in this journal for full-page ads is x ($/ad); the rate for half-page ads is y ($/ad).

The revenue for 3 full page ads are: 3x ($)

The revenue for 5 half page ads are: 5y ($)

One issue of a journal has 3 full-page ads and 5 half-page ads, generating $6340.

=> The total revenue for 3 full page and 5 half page ads are $6340

=> 3x + 5y = 6340

The revenue for 4 full page ads are: 4x ($)

The revenue for 4 half page ads are: 4y ($)

One issue of a journal has 4 full-page ads and 4 half-page ads, generating $6625.

=> The total revenue for 4 full page and 4 half page ads are $6625

=> 4x + 4y = 6625 (1)

We have:

+) 3x + 5y = 6340

=> 5y = 6340 - 3x

=> y = (6340 - 3x)/5 = 1268 - 0.6x

Replace <em>y = 1268 - 0.6x </em>into (1), we have:

4x + 4y = 6625

⇔4x + 4(1268 - 0.6x) = 6625

⇔ 4x + 5072 - 2.4x = 6625

⇔ 1.6x = 1553

⇔ x = 1553/1.6 = 970.625

=> y = 1268 - 0.6x = 1268 - 0.6*970.625= 1268 - 582.375 = 685.625

So the advertising rate for full page ads is $970.625, for half-page ads is $685.625

7 0
4 years ago
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