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3 years ago

When leaving a town, a car accelerates from 30 kmh-1 to 60 kmh-1 in 5 s. Assuming the

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

6 0

Answer:

B .62.5 m

Step-by-step explanation:

convert Kmh-1 in to ms-1

30 Kmh-1 = (30×1000) ÷3600 = 8.3ms-1

60 Kmh-1 = (60×1000) ÷3600 = 16.6 ms-1

acceleration = (16.6 - 8.3) ÷ 5 = 1.66 ms-2

V^2 = U^2 +2aS

(16.6)^2 = (8.3)^2 + 2×1.66 ×S

S = 62.5 m

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A cone has a radius of 10 cm and and height of 9 cm. What is the approximate volume of the cone? Use 3.14 for π.

astraxan [27]

Answer:

The volume of the cone is $942cm^3$

Step-by-step explanation:

The given cone has a radius of 10 cm and and height of 9 cm.

The volume of a cone is given by:

$V=\frac{\pi r^2h}{3}$

We substitute r=10 and h=9 , $\pi=3.14$ to obtain:

$V=\frac{3.14*10^2*9}{3}$

Simplify exponents to get:

$V=\frac{3.14*100*9}{3}$

Simplify:

$V=314*3\\V=942cm^3$

Therefore the volume of the cone is $942cm^3$

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3 years ago

Determine graphically if each function is even,odd,or neither.if even or odd state the symmetry

barxatty [35]

Answer:

<u>graphically</u> :

The graph is symmetrical about the origin.

Then it represents an odd function.

<u>symmetry </u>:

The origin is a center of symmetry.

8 0

1 year ago

Read 2 more answers

If i only do 8/9 assignments what will my grade be if it was 100%

Pie

Answer:

Im not sure that really makes sense but I think your grade would be 90% if you did 8/9 or somewhere around that

Step-by-step explanation:

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3 years ago

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What is the perimeter of a polygon with vertices at (3, 2) , (3, 9) , (7, 12) , (11, 9) , and (11, 2) ?

Furkat [3]

The perimeter of said polygon is 32.

5 0

2 years ago

The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation

aliina [53]

Answer:

a. X~N(2,885, 651)

b. 0.086291

c. 0.00058

d. 3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

$P(X$

#substitute the given values in the formula to solve for P:

$P(X$

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

$P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058$

Hence, the proportion of customers consuming over 5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

$0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09$

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0

3 years ago