You start by distributing: 8s-4=7s+12
Combine like terms: 8s-7s=12+4
Solve and get your answer: s=16
Answer:
-7x^3+8x^2+x-5
Step-by-step explanation:
We are simply adding the two functions:
f(x) + g(x) = (2x^2-5x^3+x-7) + (6x^2-2x^3+2) = 8x^2-7x^3+x-5 = -7x^3+8x^2+x-5
Answer:
iii) a=3b/2
Step-by-step explanation:
7a-2b= 5a+b
7a-5a=2b+b
2a=3b
a=3b/2
There are 9 marbles in the bag. We pick 2 without replacement and get a probability of 1/6.
Each draw of a marble has a probability associated with it. Multiplying these gives 1/6 so let us assume the probabilities are (1/3) and (1/2).
In order for the first draw to have a probability of 1/3 we need to draw a color that has (1/3)(9)=3 marbles. So let's say there are 3 red marbles. The P(a red marble is drawn) = 1/3.
Now that a marble has been drawn there are 8 marbles left. In order for the second draw to have a probability of 1/2 we must draw a color that has (1/2)(8) = 4 marbles. So let's say there are 4 blue marbles out of the 8.
Since there are 9 marbles to start and we have 3 red marbles and 4 blue marbles, the remaining 2 marbles must be a different color. Let us say they are green.
The problem is: There are 3 red marbles, 4 blue marbles and 2 green marbles in a jar. A marble is picked at random, it's color is noted and the marble is not replaced. A second marble is drawn at random and its color noted. What is the probability that the first marble is red and the second blue?
