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3 years ago

Which of these sequences has the largest common difference?

Mathematics

1 answer:

kotegsom [21]3 years ago

4 0

Answer:

i think it is the first one

Step-by-step explanation:

I think

You might be interested in

The arc length is 15.5 inches, the theta to the nearest hundredth of a radian is?

dlinn [17]

The answer is 305 hundredth of a radian.

6 0

4 years ago

PLEASE HELP ASAP!!

Elza [17]

Answer:

The parabolic equation does not intersect the linear equation.

Explanation:

Given equation's:

y = x² − 5x + 9
y = -2x

To solve , use substitution method by inserting 2nd equation into 1st

$\sf y = x^2 - 5x + 9$

when substituted y = -2x

$\sf -2x = x^2 - 5x + 9$

collect terms

$\sf x^2 - 5x+ 2x + 9=0$

simplify

$\sf x^2 - 3x + 9=0$

Find discriminant:

$\sf b^2 - 4ac$

$\sf (-3)^2 - 4(1)(9)$

$\sf -27$

As the discriminant is negative, it tell us that they both does not intersect each other.

7 0

2 years ago

Help help help if u can answer this I’ll mark u brainliest (6) (the one in the middle)

Hoochie [10]

You just have to plug in each thing:

So f(0):

3(0)^2 - 4 = -4

so its not A

f(-2) and f(2):

3(-2)^2 - 4

3(2)^2 -4

now we don't even have to calculate these, anything to the power of an even number is a positive number so -2^2 and 2^2 both equal 4

B is correct, so you can do the others if you want to check, but if B is true the others shouldn't be true.

4 0

4 years ago

the time taken for a ball to drop from its maximum height is directly proportional to the square root of the distance fallen. Gi

erik [133]

Answer:

=1.99 sec

Step-by-step explanation:

t=k√d

k= constant

3=k√34.1

3=5.839k

k=0.5137

t=0.5137√15

t=1.99 sec

6 0

3 years ago

National Textile installed a new textile machine in one of its factories at a cost of $250,000. The machine is depreciated linea

kirill115 [55]

Answer:

The required expression is $y=250,000-24,000 t$

Step-by-step explanation:

Consider the provided information.

National Textile installed a new textile machine in one of its factories at a cost of $250,000.

That means for 0 year the cost of the machine is $250,000.

This can be written as: (0, 250,000)

Over 10 years with a scrap value of $10,000

That means for 10 year the cost of the machine is $10,000.

This can be written as: (10, 10,000)

Now first find the rate of change:

Rate of change=m= $\frac{Rise}{Run}=\frac{10,000-250,000}{10-0}$

Rate of change=m= $\frac{Rise}{Run}=\frac{-240,000}{10}$

Rate of change=m= $\frac{Rise}{Run}=-24,000$

Now use the point-slope form of an equation of a line with the point (0, 250,000), we can find the required expression.

$(y-250,000)=-24,000(t-0)$

$y-250,000=-24,000 t$

$y=250,000-24,000 t$

Hence, the required expression is $y=250,000-24,000 t$

6 0

3 years ago