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aleksandr82 [10.1K]
2 years ago
14

What is 3x+4y=16 for x

Mathematics
1 answer:
sergiy2304 [10]2 years ago
4 0
3x + 4y = 16           Write original equation     
3x + 4y - 4y = -4y + 16          Subtract 4y from each side
3x = -4y +16                    Simplify
3x/3 = -4y/3 + 16/3      Divide each side by three
x = -4y/3 +16/3             Simplify

I hope this helps!

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Given f(x)=x2+12x+26. Enter the quadratic function in vertex form in the box. f(x)=
makvit [3.9K]

Answer:

vertex(-6,-3)

Step-by-step explanation:

x^2+12+36-36+26

(x+6)^2-10

v=(-6,-10)

4 0
3 years ago
2 Kendal bought x boxes of cookies to bring to a party. Each box contains 12 cookies. She
torisob [31]

Answer:

Hey there! The answer to your question will be below.

Step-by-step explanation:

The correct answer to your question is 12x - 24=60

So we know that 12x will be the number of cookies.

It says that she kept two boxes for herself, and than she took away 24 boxes which will leave us with 60.

Here is the work:

12 (x-2)= 60

12x-24=60

So the answer should be 12x -24 = 60

Hope this helps!

By:xBrainly

3 0
2 years ago
A rectangular room is 1.2 1.2 times as long as it is wide, and its perimeter is 35 35 meters. Find the dimension of the room.
Westkost [7]

Answer:

I. Length, L = 9.552 meters

II. Width, W = 7.96 meters

Step-by-step explanation:

Let the length = L

Let the width = W

Given the following data;

Perimeter = 35 m

Translating the word problem into an algebraic equation, we have;

Length = 1.2W

To find the dimension of the room;

The perimeter of a rectangle is given by the formula;

P = 2(L + W)

Substituting into the formula, we have;

35 = 2(1.2W + W)

35 = 2(2.2W)

35 = 4.4W

Width, W = 7.96 meters

Next, we would find the length of the rectangle;

L = 1.2*W

L = 1.2 * 7.96

Length, L = 9.552 meters

6 0
3 years ago
On the graph shown, what is f(-2)
WARRIOR [948]

Answer:

3 because when x=2 the lines are at y 1 and 3, but the y 1 isn't shaded, so the answer is 3

3 0
2 years ago
PLEASE HELP 100 POINTS!!!!!!
horrorfan [7]

Answer:

A)  See attached for graph.

B)  (-3, 0)  (0, 0)  (18, 0)

C)   (-3, 0) ∪ [3, 18)

Step-by-step explanation:

Piecewise functions have <u>multiple pieces</u> of curves/lines where each piece corresponds to its definition over an <u>interval</u>.

Given piecewise function:

g(x)=\begin{cases}x^3-9x \quad \quad \quad \quad \quad \textsf{if }x < 3\\-\log_4(x-2)+2 \quad  \textsf{if }x\geq 3\end{cases}

Therefore, the function has two definitions:

  • g(x)=x^3-9x \quad \textsf{when x is less than 3}
  • g(x)=-\log_4(x-2)+2 \quad \textsf{when x is more than or equal to 3}

<h3><u>Part A</u></h3>

When <u>graphing</u> piecewise functions:

  • Use an open circle where the value of x is <u>not included</u> in the interval.
  • Use a closed circle where the value of x is <u>included</u> in the interval.
  • Use an arrow to show that the function <u>continues indefinitely</u>.

<u>First piece of function</u>

Substitute the endpoint of the interval into the corresponding function:

\implies g(3)=(3)^3-9(3)=0 \implies (3,0)

Place an open circle at point (3, 0).

Graph the cubic curve, adding an arrow at the other endpoint to show it continues indefinitely as x → -∞.

<u>Second piece of function</u>

Substitute the endpoint of the interval into the corresponding function:

\implies g(3)=-\log_4(3-2)+2=2 \implies (3,2)

Place an closed circle at point (3, 2).

Graph the curve, adding an arrow at the other endpoint to show it continues indefinitely as x → ∞.

See attached for graph.

<h3><u>Part B</u></h3>

The x-intercepts are where the curve crosses the x-axis, so when y = 0.

Set the <u>first piece</u> of the function to zero and solve for x:

\begin{aligned}g(x) & = 0\\\implies x^3-9x & = 0\\x(x^2-9) & = 0\\\\\implies x^2-9 & = 0 \quad \quad \quad \implies x=0\\x^2 & = 9\\\ x & = \pm 3\end{aligned}

Therefore, as x < 3, the x-intercepts are (-3, 0) and (0, 0) for the first piece.

Set the <u>second piece</u> to zero and solve for x:

\begin{aligned}\implies g(x) & =0\\-\log_4(x-2)+2 & =0\\\log_4(x-2) & =2\end{aligned}

\textsf{Apply log law}: \quad \log_ab=c \iff a^c=b

\begin{aligned}\implies 4^2&=x-2\\x & = 16+2\\x & = 18 \end{aligned}

Therefore, the x-intercept for the second piece is (18, 0).

So the x-intercepts for the piecewise function are (-3, 0), (0, 0) and (18, 0).

<h3><u>Part C</u></h3>

From the graph from part A, and the calculated x-intercepts from part B, the function g(x) is positive between the intervals -3 < x < 0 and 3 ≤ x < 18.

Interval notation:  (-3, 0) ∪ [3, 18)

Learn more about piecewise functions here:

brainly.com/question/11562909

3 0
1 year ago
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