this can be solve using newtons heating of cooling
(Ts – T) =(Ts – To)*e^(-kt)
Where Ts is the ambient temperature
To is initial temperature
T is the temperature at time t
t is the time
k is constant
fisrt solve the constant k for the given first scenario
(99 – 36) = (99 – 46)*e(-5k)
K = -0.0346
Using k, solve T at t = 13 min
(99 – 46) = (99 – T)*e(-13*(-0.0346)
T = 58.82 degree F
Answer:
About $735.03
Step-by-step explanation:
The compound interest formula is A=P(1+r/n)^nt
P is the original amount (principal)
r is the rate
n is the number of times compounded (1 for this one since it is annual)
and t is the time compounded
Answer:
A
Step-by-step explanation:
-9.75 + 3.25x
3.25(-3 + x)
-3.25(3 - x)
