6 eggs per hen if you set up proportions.
15 hens 1 hen
_______ = ______
90 eggs x eggs
Cross multiply.
15x=90
Divide.
90/15= 6 eggs per hen
Answer:
A conic section that can be thought of as an inside-out ellipse
Step-by-step explanation:
15/10 which equals 1 5/10 which equals 1 1/2
Answer:
The answer is D
Step-by-step explanation:
Looking at the image, the points are lettered. The question asks you to give the ordered pair these points fall on. The Y Axis is up and down. The X is left to right.
Answer:
The probability that sum of numbers rolled is a multiple of 3 or 4 is:
.
Step-by-step explanation:
The sample space for two fair die (dice) is given below:
![\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&2&3&4&5&6&7\\2&3&4&5&6&7&8\\3&4&5&6&7&8&9\\4&5&6&7&8&9&10\\5&6&7&8&9&10&11\\6&7&8&9&10&11&12\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccccc%7D%261%262%263%264%265%266%5C%5C1%262%263%264%265%266%267%5C%5C2%263%264%265%266%267%268%5C%5C3%264%265%266%267%268%269%5C%5C4%265%266%267%268%269%2610%5C%5C5%266%267%268%269%2610%2611%5C%5C6%267%268%269%2610%2611%2612%5Cend%7Barray%7D%5Cright%5D)
From the above table:
Number of occurrence where sum is multiple of 3 = 12
Number of occurrence where sum is multiple of 4 = 9
Total number in the sample space = 36
probability(sum is 3) = 12/36
probability(sum is 4) = 9/36
probability(sum is 3 or 4) ![=\frac{12}{36} +\frac{9}{36} \\=\frac{12 + 9}{36} \\=\frac{21}{36}\\=\frac{7}{12}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B12%7D%7B36%7D%20%2B%5Cfrac%7B9%7D%7B36%7D%20%5C%5C%3D%5Cfrac%7B12%20%2B%209%7D%7B36%7D%20%5C%5C%3D%5Cfrac%7B21%7D%7B36%7D%5C%5C%3D%5Cfrac%7B7%7D%7B12%7D)