<span>y-2>1/2(x-2) can be expanded as follows: y - 2 > (1/2)x - 1

Mult. all terms by 2 to remove the fractions:

2y - 4 > x - 2

Add 4 to both sides: 2y > x + 2

Div. both sides by 2: y > (1/2)x + 1 (answer)</span>

4 0

3 years ago

Supposed that you balance your checkbook and find that you are overdrawn by $18; that is, your balance is -$18. Then you go to t

vlada-n [284]

Answer:

I need helpp

Step-by-step explanation:

Peeople looking at this please check mine at unanswered im at desperte helpp!!!!

mine is just above this on unanswered<3 smluv

3 0

3 years ago

Read 2 more answers

HELP PLEASE,<br><br> Part a of the question was posted earlier on.

Elanso [62]

$\bf \lim\limits_{x\to 6}~\cfrac{x^2+x+42}{x-6}\implies \lim\limits_{x\to 6}~\cfrac{(x+7)(x-6)}{(x-6)}\implies \lim\limits_{x\to 6}~x+7
\\\\\\
\lim\limits_{x\to 6}~(6)+7=13
\\\\\\
\textit{since the original equation holds for all, }x\ne 6,\textit{ then it approaches}\\
\textit{the same limit as }x+7$

3 0

3 years ago