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2 years ago

Please help me answer this :) I will give Brainlst

Mathematics

1 answer:

azamat2 years ago

4 0

Answer:

From the given graph above

It is a not a function

Function has only one output for each input

It does not pass the vertical line test

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Select all ratios equivalent to 1:8.

DochEvi [55]

Answer: 2:16 - 3:24 - 4:32 - 5:40 - 6:48 - 7:56 - 8:64 // just keep adding each side to its own side

Step-by-step explanation:

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3 years ago

9 = v + 4 v + 12<br><br> help me with this

True [87]

Answer:

v=-3/5

Step-by-step explanation:

9 = v + 4 v + 12

=>5v=9-12

=>v=-3/5

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4 years ago

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What number is 264% of 25?

Evgen [1.6K]

Answer:

9.47

Step-by-step explanation:

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3 years ago

The side across from the right angle is called a leg. <br> a. True<br> b. False?

horrorfan [7]

False, the side across from the right angle is called the hypotenuse

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3 years ago

Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have points (1,6) and (2,2)

Slope is:

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2$

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11$

The equation of line will be:

$y=mx+b\\y=-2x+11$

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1$

The equation of line will be:

$y=mx+b\\y=\frac{1}{2}x+1$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

6 0

3 years ago