Here speed of first train is slower than speed of second train. So if they catch up , the distance traveled will be same since they left the same station at different times.
But the time traveled will be different .
Let us say the two trains meet at time t ,
Distance = speed * time
Distance traveled by first train = 40 t
Since second train is leaving after three hours , so
Distance traveled by second train = 60(t-3)
As discussed earlier, distance traveled will be same, so
distributing 60 over t-3
t=9
So the second train will meet the first at 9 p.m.
Answer:
(Missing part of the question is attached)
Estimates are too large.
Step-by-step explanation:
Suppose the only information we know about the function is:
where the graph of its derivative is shown in the attachment
<h3>(a)</h3>
If the function 
is differentiable at point 
, the tangent line to the graph of 
at 1 is given by the equation:
So we call the linear function:
We know the as it is given in the question, and 
from the graph attached. Substitute in the equation of 
.
<h3>(b)</h3>
At x=1, 
is positive but it is decreasing. However. if we draw the tangent lines, we see that the tangent lines are becoming less steeper, so the tangent lines lie above the curve . Thus, The estimates are too large.
Well first you have to know what i is. i is the sqrt of -1 so try doing 3+5(sqrt-1)/1+sqrt-1. I don't know how to solve it though sorry
<span>The smaller share is equal to 9.51 rounded to 2 decimal places.
</span>
