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3 years ago

Precalc Help me Please

Mathematics

1 answer:

Likurg_2 [28]3 years ago

7 0

We just need to solve for y when x = -2

Solution:

y = 2|-2 + 1|

y = 2|-1|

y = 2(1)

y = 2

Therefore, the answer is Option 3

Best of Luck!

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Drag the tiles to the correct boxes to complete the pairs.

Len [333]

<u>Answer:</u>

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4} \implies 2^{-32}$

2. $2^4 . (2^2)^{-2} \implies 1$

3. $(-2^{-4}).(2^2)^0 \implies -2^8$

4. $(2^2).(2^3)^{-3} \implies 2^{-5}$

<u>Step-by-step explanation:</u>

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4}$ :

$= \frac{ ( - 2 ^ 2 ) ^ { - 6 } } { ( 2 ^ { - 5 } ) ^ { - 4 } } = \frac{2^{-12}}{2^{20}} = 2^{-12-20}=2^{-32}$

2. $2 ^ 4 . ( 2 ^ 2 ) ^ { - 2 }$ :

$= 2^4 \times \frac{1}{2^4} = 1$

3. $(-2^{-4}).(2^2)^0$ :

$= (-2^4)^2 \times 1 = -2^8$

4. $(2^2).(2^3)^{-3}$ :

$= 2^4 \times \frac{1}{2^9} =\frac{1}{2^5} =2^{-5}$

5 0

3 years ago

Read 2 more answers

You recently opened your checking account with reallybigbank on August 1 using $100.00

WITCHER [35]

What's the question:

whats the question

What's the question:

whats the question

5 0

2 years ago

A glitter glue recipe takes a mixture of 1 5 cup of glitter to 2 5 cup of glue. For A, how many cups of glitter are used for 1 c

tatiyna

0.6 cup of gliter is used for 1 cup of glue and 1.6 cup of gliter glue is made with 1 cup of glue.

Part A

Given that,

15 cup of gliter is for 25 cup of glue ,

Therefore, "X" cup of gliter is for 1 cup of glue

X = (1*15)/25

X= 0.6 cup of gliter

Part B,

Given that,

From part A 0.6 cup of gliter is for 1 cup of glue

Thus, 1 cup of glue and 0.6 cup of gliter when mixed will form "Y" cup of gliter glue

Now, Y= 0.6 cup of gliter + 1 cup of glue

Y= 1.6 cup of gliter glue

which approximates to 2 cup of gliter glue.

For more information on cross multiplication kindly visit to

brainly.com/question/11203238

3 0

1 year ago

IF TUPAC RAN 35 miles Away From BIGGIE SMALLS. IF BIGGIE ran 3 miles but didnt catch TUPAC how far away was TUPAC

Masteriza [31]

Answer:

Well after Biggie ran 3 miles Tupac would be 32 miles away from biggie.

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

We are throwing darts on a disk-shaped board of radius 5. We assume that the proposition of the dart is a uniformly chosen point

Vlad1618 [11]

Answer:

the probability that we hit the bullseye at least 100 times is 0.0113

Step-by-step explanation:

Given the data in the question;

Binomial distribution

We find the probability of hitting the dart on the disk

⇒ Area of small disk / Area of bigger disk

⇒ πR₁² / πR₂²

given that; disk-shaped board of radius R² = 5, disk-shaped bullseye with radius R₁ = 1

so we substitute

⇒ π(1)² / π(5)² = π/π25 = 1/25 = 0.04

Since we have to hit the disk 2000 times, we represent the number of times the smaller disk ( BULLSEYE ) will be hit by X.

X ~ Bin( 2000, 0.04 )

n = 2000

p = 0.04

np = 2000 × 0.04 = 80

Using central limit theorem;

X ~ N( np, np( 1 - p ) )

we substitute

X ~ N( 80, 80( 1 - 0.04 ) )

X ~ N( 80, 80( 0.96 ) )

X ~ N( 80, 76.8 )

So, the probability that we hit the bullseye at least 100 times, P( X ≥ 100 ) will be;

we covert to standard normal variable

⇒ P( X ≥ $\frac{100-80}{\sqrt{76.8} }$ )

⇒ P( X ≥ 2.28217 )

From standard normal distribution table

P( X ≥ 2.28217 ) = 0.0113

Therefore, the probability that we hit the bullseye at least 100 times is 0.0113

3 0

3 years ago