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faust18 [17]
3 years ago
10

11. Jim travelled at a speed of 18km/h for 2 hours. What was the distance covered?​

Mathematics
1 answer:
Igoryamba3 years ago
7 0

Answer:

d = 36 km

Step-by-step explanation:

Speed of Jim, v = 18 km/h

Time, t = 2 hours

We need to find the distance covered. We know that the speed of an object is equal to the distance covered by it divided by total time taken.

v=\dfrac{d}{t}\\\\d=v\times t\\\\d=18\ km/h\times 2\ h\\\\=36\ km

So, he will cover 36 km.

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With a family bowling pass, families can bowl for $4 per game . The pass cost $10 per year. Use equation , a table and a graph t
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Answer:

Part a) a=4g+10 (see the explanation)

Part b) see the explanation

Part c) The graph in the attached figure

Step-by-step explanation:

<u><em>The complete question is</em></u>

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

a ----> the total amount of money spent on bowling in a year

g ---> the number of games a family plays in a year

we know that

The linear equation in slope intercept form is equal to

a=mg+b

where

m is the slope or unit rate

b is the a-intercept or initial value

In this problem we have

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substitute

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Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> a=4(0)+10=\$10

For g=1 ----> a=4(1)+10=\$14

For g=2 ----> a=4(2)+10=\$18

For g=3 ----> a=4(3)+10=\$22

For g=4 ----> a=4(4)+10=\$26

The table is

\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]

Part c) Use the values from your table to draw a graph

we have the ordered pairs

(0,10),(1,14),(2,18),(3,22),(4,26)

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