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fredd [130]
3 years ago
11

Bryce and Rachel are collecting canned goods for the local food bank. Bryce's goal is to collect 32 items. Rachel's goal is to c

ollect 24 items. If Rachel and Bryce each meet their goal, what fraction of Bryce's goal does Rachel collect?
Mathematics
1 answer:
vlabodo [156]3 years ago
4 0
I think the fraction would be 3/4.
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12345 [234]
Answer should be 63 because you multiply to find area
8 0
3 years ago
If q→ p is true, then ~ p → ~ q is _____ true. always sometimes never
Bogdan [553]

Answer: always

Step-by-step explanation:

6 0
3 years ago
Chris bought 4 hot dogs for $1.50. Which of the following shows an equivalent rate?
o-na [289]

Answer:

1 hot dog for$0.50

Step-by-step explanation:

i hope these answer is correct

3 0
2 years ago
Order these numbers for lest to greatest 1/2 ,1.1 ,5/3 ,2, 0 ,0.4, -2 ,5/8
Nat2105 [25]

The least number should always start off with negatives if there are any. In this case there is so we can start with -2 as our least amount. Next are the small fractions. If you're allowed a calculator, I would use that to find what the decimals will look like for each fraction:

\frac{1}{2} =0.5\\ \\ \frac{5}{3} =1.6666666666666666666666666666667\\ \\ \frac{5}{8} =0.625

After -2 the next least number is 0 and the next one is the fraction or decimal closest to the number 0 which is 0.4

The next number would be from the fractions we solved earlier. 0.5 and 0.625 would follow 0.4 and then 1.1 and 1.6667(solved for from fraction).

Here is the list:

-2,0,0.4,\frac{1}{2} ,\frac{5}{8} ,1.1,\frac{5}{3}

Hope this helps!


6 0
3 years ago
Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1
harkovskaia [24]
y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\&#10;y''(0)=20\cdot0^3=0

The value of the second derivative for x=0 is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of 5x^4 is always positive for x\in\mathbb{R}\setminus \{0\}. That means at x=0 there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval [-2,1].
The function y is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

y_{max}=y(1)=1^5-3=-2
4 0
3 years ago
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