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Bumek [7]
3 years ago
7

The school bleachers measure 25 feet from the floor diagonally to the top seat. They extend 20 feet from the back wall.

Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

d

Step-by-step explanation:

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Whats the lcm of 8 and 10
Firdavs [7]
The answer is 40. Hope this helped! Between 8 and 10, you can determine the least common multiple by multiplying. 8*5=40, and 10*4=40.
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To find the length of a line segment given endpoints is to use ______
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Answer:

To calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. * i didnt know what to put so i put this*

8 0
2 years ago
At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
xz_007 [3.2K]

Answer:

D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=(14-1)=13\ years\\ P=\$250\\r=0.03

substitute in the formula above

A=\$250(1+0.03*13)

A=\$250(1.39)=\$347.50

8 0
3 years ago
The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)

\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

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Answer:   how much does an exam cost XD?

Step-by-step explanation:

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