Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
The ratio of three numbers are 2:3:4.
Let the rational between the three numbers be x, hence the three numbers be 2x, 3x,and 4x.
If their average is 36, what are the numbers
We know the average = sum of the numbers / no. Of numbers.
(2x+3x+4x) /3=36
9x/ 3= 36
3x =36
X= 36/ 3
X= 12
The rational is 12
Answer the three number are 24, 36, and 48.
HOPE THIS HELP!!
Answer:
The answer is
Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
Q(2,4) and R(-3,9)
The midpoint is
We have the final answer as
Hope this helps you
Hi
how are u in need points
Answer:
False
Step-by-step explanation:
4x + y < 2
y > –2
Substitute the point into the inequalities and see if they are true
4(4) + 2 < 2
16+2 < 2
18 <2 False
2 > –2 True
Since one is false the point is not a solution
