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2 years ago

You don't have to do them all

Mathematics

1 answer:

Levart [38]2 years ago

3 0

Answer:

First one is 5, second one is 6, third one is 6, the last one is 2

Step-by-step explanation:

Hope this helps an mark brainliest please!

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75 POINTS. I WILL GIVE BRAINLIEST.

agasfer [191]

Question 5, x could be either 6 or -1.

3 0

3 years ago

Read 2 more answers

On a coordinate plane, triangle A B C has points (negative 3, negative 1), (negative 2, negative 3), (1, negative 1) and is refl

andreev551 [17]

Answer:

A' = (-3, 3)

Step-by-step explanation:

If the points are as follows:

A = (-3, -1)

B = (-2, -3)

C = (1, -1)

When reflecting across a y axis the x values remain the same.

When reflecting across y = 1 the y values will remain equal distant from y = 1.

A' = (-3, 3) y value = |-1 - 1| = 2 + 1 = 3

B' = (-2, 5) y value = |-3 - 1| = 4 + 1 = 5

C' = (1, 3) y value = |-1 - 1| = 2 + 1 = 3

7 0

3 years ago

A 90 percent confidence interval for the slope of a regression line is determined to be (-0.181, 1.529). Which of the following

GenaCL600 [577]

Answer: a. The correlation coefficient of the data is positive.

Step-by-step explanation:

Estimated slope of sample regression line = $\dfrac{Upper \ limit + lower\ limit}{2}$

Here , confidence interval : (-0.181, 1.529)

Estimated slope of sample regression line = $\dfrac{-0.181+1.529}{2}$

$=\dfrac{1.348}{2}\\\\=0.674\ \ \ \ [\text{ positive}]$

⇒Correlation coefficient(r) must be positive, So a. is true.

But, d. and e. are wrong(0.674 ≠ 0 or 1.348).

We cannot check residuals or its sum from confidence interval of slope of a regression line, so b is wrong.

We cannot say that scatterplot is linear as we cannot determine it from interval, so c. is wrong

So, the correct option : a. The correlation coefficient of the data is positive.

7 0

3 years ago

What value does the 1 in the number 4,105.8

kirill115 [55]

Answer:

hundreds

Step-by-step explanation:

4 0

3 years ago

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How to solve 2(x+y)^2-9(x+y)-5

Aliun [14]

Answer:

2(x + y)² - 9( x + y ) -5 = 0

⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0

⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0

taking (x + y -5 ) common ,

⇒(x + y -5 )[2(x + y) + 1] =0

⇒(x + y -5)(2x + 2y +1) =0

hope , you got this

6 0

3 years ago