Answer:
per il vertice basta che usi la formula: V (-b/2a ; - delta/4a)
asse x : -b/2a
Step-by-step explanation:
here is your answer to your work plz rate me the most brainlest
yep this is a triangle becasue to side are the same
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
Answer:
- (x + 10)² + (y + 4)² = 232
Step-by-step explanation:
<h3>Given </h3>
- Center = (-10, -4)
- Point on circle = (4, 2)
<h3>To find </h3>
<h3>Solution</h3>
<u>Remember the standard equation of circle:</u>
- (x - h)² + (y - k)² = r², where (h, k) is the center and r is radius
<u>We have</u>
Use distance formula (Pythagorean theorem) to work out the length of the radius. We know that radius is the distance from the center to any point on the circle.
<u>Here we are finding the distance between points (-10, -4) and (4, 2)</u>
- r² = (-10 - 4)² + (-4 - 2)²
- r² = 14² + 6²
- r² = 232
<u>So the equation is:</u>
- (x + 10)² + (y + 4)² = 232