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ValentinkaMS [17]
2 years ago
14

Heeelllppp me please :)

Mathematics
1 answer:
Sophie [7]2 years ago
4 0
The common ratio is 3.

I hope this helps!
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Ashley multiplied 9 x 0.942 and got 84.78. How can you use estimation to show that Ashley's answer is wrong? Use whole numbers t
exis [7]

Answer:

Calculate the percent value:

0.942 =

0.942 × 100/100 =

(0.942 × 100)/100 =

94.2/100 =

94.2%;

In other words:

1) Multiply that number by 100.

2) Add the percent sign % to it.

Answer:

0.942 = 94.2%

Step-by-step explanation:

7 0
3 years ago
A person is running a distance race at a constant rate. What time will they finish the race what information would you need to b
Zinaida [17]

Answer:

you need the distance they're running and the pace they are running at.

3 0
2 years ago
Read 2 more answers
7260÷91= please show the work
Degger [83]
7260÷91

91 goes into 726 7 times

with 890 left 91 goes into it 9 time with the remainder of 71


the answer is 79 r 71
6 0
2 years ago
Which expression has a value that is equivalent to the given expression when n = 8?
mrs_skeptik [129]

Q1.

Put the value of n = 8 to the expressions:

2n + 10 → 2(8) + 10 = 16 + 10 = 26

A: 3n → 3(8) = 24 ≠ 26

B: 2(n + 5) → 2(8 + 5) = 2(13) = 26   :)

C: n² + 5 → 8² + 5 = 64 + 5 = 69 ≠ 26

D: 10n + 2 → 10(8) + 2 = 80 + 2 = 82 ≠ 26

<h3>Answer: B: 2(n + 5)</h3>

Q2.

x = 3, y = 2

L = 5y² - 2x → L = 5(2)² - 2(3) = 5(4) - 6 = 20 - 6 = 14

R = x² + ... → R = 3² + ... = 9 + ...

A: x² + x → 9 + 3 = 12  NOT

B: x² + y → 9 + 2 = 11   NOT

C: xy → 9 + (3)(2) = 9 + 6 = 15 YES

D: 2y → 9 + (2)(2) = 9 + 4 = 13   NOT

5y² - 2x < x² + xy

L = 14, R = 15, L < R    CORRECT

<h3>Answer: C: xy</h3>

Q3.

3 + 6² = 3 + 36 = 39

A: 3³ + 12 = 27 + 12 = 39  NOT

B: 5² + 4² = 25 + 16 = 41 > 39    YES

C: 2³ + 5² + 6 = 8 + 25 + 6 = 39    NOT

D: 2³ + 14 + 17 = 8 + 14 + 17 = 39    NOT

<h3>Answer: B: 3 + 6² < 5² + 4²</h3>
6 0
3 years ago
To find 10, Beau found 32 = 9 and 42 = 16. He said that since 10 is between 9 and 16, 10 is between 3
AlexFokin [52]

Given that:

Consider it is \sqrt{10} instead of 10 on two places.

\sqrt{10} is between 3  and 4. So, Beau thinks a good estimate for \sqrt{10} is = 3.5.

Solution:

To find \sqrt{10}, Beau found 3² = 9 and 4² = 16.

He said that since 10 is between 9 and 16.

Since 10 is close to 9, therefore \sqrt{10} must be close to 3. So, Beau's estimate is high.

Now,

(3.1)^2=9.61

(3.2)^2=10.24

Since, 10 lies between 9.61 and 10.24, therefore \sqrt{10} must be lies between 3.1 and 3.2.

\dfrac{3.1+3.2}{2}=3.15

Therefore, the estimated value of \sqrt{10} is 3.15.

4 0
3 years ago
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