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xeze [42]
3 years ago
9

X is on line WY. Find the value of b.

Mathematics
2 answers:
o-na [289]3 years ago
8 0
The answer is 85

explanation: x=180

now you just have to subtract 85 from 180 and you get 85
Free_Kalibri [48]3 years ago
7 0
The answer is 51 degrees
Explanation: all the angles above line WY have to equal 180 degrees, you add the 95 and 34 and get 129, then you subtract that from 180 and get 51
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HELP QUICK!!! :O WILL BRAINLIEST
Marianna [84]
A. you have to do the whole 30/2  i just had this on a test. GOOD LUCK 
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3 years ago
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Find the total surface area of the<br> following square pyramid:<br> 9 cm<br> 10 cm<br> SA = [?]cm2
MakcuM [25]

Answer:

280 cm2

Step-by-step explanation:

1)find the area of square

A=LW

=10×10

=100

2) find the area of triangle

A=B×H÷2

=10×9/2

=45

Coz,there are 4 triangle we multiple by 4

=45×4

=180

3)find the total surface area by adding the two

=100+180

=280cm2

4 0
2 years ago
A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each
Nadya [2.5K]

Answer:

312.5\pi \text{ km}^3\approx 981.75\text{ km}^3

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}, where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3

Therefore, the volume of earth removed to build the three tunnels is 312.5\pi \text{ km}^3\approx 981.75\text{ km}^3.


4 0
3 years ago
HELP ME!! SOMEBODY PLEASE HELP ME
IRISSAK [1]
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x^2 - 9x - 36 = 0
(x -12)(x + 3) = 0
x - 12 = 0; x = 12
x +3 = 0; x = -3

so in this case x = 12 then DC = 12 - 9 = 3

y^2 = 12^2 - 6^2
y^2 = 144 - 36
y^2 = 108
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scoray [572]

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