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denpristay [2]
2 years ago
9

5x + 7 = 2x - 8 can anyone say how to solve please ​

Mathematics
1 answer:
SCORPION-xisa [38]2 years ago
4 0

Answer:

x = - 5

Step-by-step explanation:

Given

5x + 7 = 2x - 8 ( subtract 2x from both sides )

3x + 7 = - 8 ( subtract 7 from both sides )

3x = - 15 ( divide both sides by 3 )

x = - 5

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Monica [59]
Well the y=mx+b equation for your question is -2x-6 so if you plug 6 in for x, then you will get -2(6)-6, and when you simplify that it is -18.

So k=-18

3 0
2 years ago
Please help explanation if possible
Svet_ta [14]

Answer:

18.84 feet.  let me know if you have ay other questions.

Step-by-step explanation:

The way to find the formula for circumference is kinda complicated so it is best to ust memorize the formula, which is 2πr.  or 2 times pi times the radius.  

Your problem gives you the formula, but instead of 2 and r in it you have d, which is the diameter.

The diameter of the circle is 2 times the radius, so that's why it is replaced.

the radius is the distance from the center fo the circle to one edge, and the diameter is the distance through the circle passing through its center.  so it's the center to one end plus the center to another end.  or r+r which is also 2r.

So d = 2r, so in this problem d =6 feet.

So now the formula πd = 3.14*6 feet = 18.84 feet

7 0
3 years ago
What is the area of a rectangle that measures 9 cm by 4 cm
andrew-mc [135]
The answer would be 36
3 0
3 years ago
Find the sum<br> 4 1/2 + 5 1/2
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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The ball used in a soccer game may not weigh more than 16 ounces or less
Liono4ka [1.6K]
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.

So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.

x + 1.5 = 14
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The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces

x + 1.5 = 16
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From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
3 0
3 years ago
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