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3 years ago

What is the area of the figure below?

Mathematics

2 answers:

svetlana [45]3 years ago

8 0

24 cm sq is the answer

miv72 [106K]3 years ago

8 0

Answer:

Step-by-step explanation:

5 times 4 = 20

2 times 2 = 4

20 + 4 = 24

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What is 20/45 simplified

Andre45 [30]

4/9, is your answer.
Both numerator and denominator can go into 5.
20 divided by 5 is 4, 45 divide by 5 is 9.

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3 years ago

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Given that rectangle LMNO with coordinates L(0,0), M(3,0), N(3,7), O(0,7), P is the midpoint of LM⎯⎯⎯, and Q is the midpoint of

Elina [12.6K]

The midpoint of a line divides the line into equal segments.

The option that proves PQ = LO is (a)

The given parameters are:

$\mathbf{L = (0,0)}$

$\mathbf{M = (3,0)}$

$\mathbf{N = (3,7)}$

$\mathbf{O = (0,7)}$

P is the midpoint of LM.

So, we have:

$\mathbf{P = \frac{LM}{2}}$

$\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}$

$\mathbf{P = (\frac{3}{2},0)}$

Q is the midpoint of NO.

So, we have:

$\mathbf{Q = \frac{NO}{2}}$

$\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}$

$\mathbf{Q = (\frac{3}{2},7)}$

Distance PQ is calculated as follows:

$\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

This gives:

$\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}$

$\mathbf{PQ = \sqrt{ 7^2}}$

$\mathbf{PQ = 7}$

Distance LO is calculated as follows:

$\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}$

$\mathbf{LO = \sqrt{ 7^2}}$

$\mathbf{LO=7}$

So, we have:

$\mathbf{PQ = 7}$

$\mathbf{LO=7}$

Thus:

$\mathbf{PQ = LO}$

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

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2 years ago

Can someone please help ASAP (solving rational equations)

aivan3 [116]

The answer is c, x=1

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3 years ago

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A kite is being flown at a 45 angle. The string of the kite is 120 feet long. How high is the kite above the point at which the

MrRissso [65]

Answer: The height of the kite above the point at which the string is held is $120\sqrt{2}$ feet.

Step-by-step explanation:

Given : A kite is being flown at $45^{\circ}$ . The string of the kite is 120 feet long.

Let AB denote the string of kite and AC be the height of the kite above the point at which the string is held.

Now, in right Δ ABC

$\sin45^{\circ}=\frac{AC}{AB}\\\Rightarrow\ \frac{1}{\sqrt{2}}=\frac{AC}{120}\\\Rightarrow\ AC=120\sqrt{2}$

hence, The height of the kite above the point at which the string is held is $120\sqrt{2}$ feet.

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A chemist is using 333 milliliters of a solution of acid and water. If 17.2% of the solution is acid, how many milliliters of ac

lozanna [386]

57 milliliters of acid

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3 years ago