All categories

3 years ago

Hii, does anyone know a example for 28 + 29? thanks

Mathematics

2 answers:

MissTica3 years ago

5 0

Answer:

the answer is 57

Step-by-step explanation:

Johny has 28 apples and his mom gave him 29 more apples, johny now has 57 apples.

kaheart [24]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Write 70 cm as a fraction of 2meters

vazorg [7]

Answer:

70cm/200cm

Step-by-step explanation:

math

5 0

3 years ago

Read 2 more answers

Allan bought a rug shaped as a semicircle that has a radius of 4 yards. What is the circumference of the rug? Plz answer

pentagon [3]

Circumference = 2 x pi x radius

2 x pi x 4 = 25.13 yards
(correct to 2 decimal places)

Hope this helps!!

3 0

3 years ago

Find the value of x & z plz and give an explanation ( :

inessss [21]

Answer:

x = 6√2
x = √3

Step-by-step explanation:

1. You have correctly written the relationship between the side lengths and the length of the hypotenuse for these isosceles right triangles.

For this problem, you simply need to multiply the side length by √2. The length of the hypotenuse is then ...

x = 6√2

___

2. The side length multiplied by √2 is √6. You know

√6 = √(2·3) = (√2)(√3) = (√2) · (side length)

so we know that x = √3.

7 0

4 years ago

GIVE AN EXPLANATION PLEASE! 20 POINTS!! AND A BRAINLEEST IF TWO OR MORE PEOPLE HAVE ANSWERED IT. (FIRST COME FORST SERVE BASES +

Vlad1618 [11]

witw6oweo6ssitsi5sutaurzhfztzjxisi5

4 0

3 years ago

A rhombus has a side length equal to one of the diagonals. The other diagonal is 4cm longer. Find the area of the rhombus.

klasskru [66]

Answer:

The area of the rhombus is 25.83 cm².

Step-by-step explanation:

The area of a rhombus is given by:

$A = \frac{d_{1} \times d_{2}}{2}$

Where:

d₁: is one diagonal

d₂: is the other diagonal = d₁ + 4 cm

We know that one side length of the rhombus is equal to d₁. We can imagine a right triangle inside the rhombus, with the following dimensions:

h: hypotenuse of the right triangle

a: one side of the right triangle

b: is the other side of the right triangle

From the above we know that:

h = d₁

$a = \frac{d_{2}}{2} = \frac{d_{1} + 4}{2}$

$b = \frac{d_{1}}{2}$

We can find d₁ with Pitagoras:

$h^{2} = a^{2} + b^{2}$

$d_{1}^{2} = (\frac{d_{1} + 4}{2})^{2} + (\frac{d_{1}}{2})^{2}$

$d_{1}^{2} = \frac{1}{4}(d_{1}^{2} + 8d_{1} + 16 + d_{1}^{2})$

By solving the above quadratic equation for d₁ and taking the positive solution we have:

$d_{1} = 5.46 cm$

So, d₂ is:

$d_{2} = d_{1} + 4 = 5.46 cm + 4 cm = 9.46 cm$

Now, we can find the area:

$A = \frac{d_{1} \times d_{2}}{2} = \frac{5.46 cm \times 9.46 cm}{2} = 25.83 cm^{2}$

Therefore, the area of the rhombus is 25.83 cm².

I hope it helps you!

3 0

3 years ago