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2 years ago

A kite was broken into two triangles.

Mathematics

1 answer:

ASHA 777 [7]2 years ago

4 0

That’s all the information that there is oh well it’s C but I need more information to make sure

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The cost of a jacket increased from $95.00 to $107.35. what is the percentage increase of the cost of the jacket?

lidiya [134]

It would be 35%. Hope this helps.

6 0

2 years ago

Find the value of x in the figure

gregori [183]

Step-by-step explanation:

I hope the picture is visible

7 0

2 years ago

How many units above the x-axis is the point located at (9, 6)? pls help

svetlana [45]

Answer:

6 units above the x-axis

Step-by-step explanation:

The pair (9,6) are a set of coordinates that indicate how far away from the origin (0,0) the point is.

The coordinates are written (x,y) where 'x' is how far to the left or right of the y-axis (vertical) the point is. The 'y' is how far above or below the x-axis (horizontal) the point is.

So in this case, the set of (9,6) means that the point is located at 9 units to the right of the origin and the y-axis and 6 units above the x-axis

4 0

2 years ago

Read 2 more answers

Lola is using a one-sample t-t- test for a population mean, µμ , to test the null hypothesis, H0:µ=40 mg/dLH0:μ=40 mg/dL , again

gavmur [86]

Answer:

d. She should reject the null hypothesis because p < 0.10.

Step-by-step explanation:

We have a t statistic, so let's solve for the P-value on our calculators. (tcdf on a TI-84 calculator is 2nd->VARS->6.)

tcdf(left bound, right bound, degrees of freedom)

Our left bound is t=1.457.

Our right bound is infinity, because we're interested in the hypothesis µ>40 mg/dL. We use 999 to represent infinity in the calculator.
Our degrees of freedom is n-1 = 15-1 = 14.

tcdf(1.457,999,14) = .084

.084 < P-value of .10, so we reject the null hypothesis.

4 0

3 years ago

Graphs of Function,

andrew-mc [135]

Answer:

A function is increasing when the gradient is positive

A function is decreasing when the gradient is negative

Question 7

If you draw a tangent to the curve in the interval x < -2 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve in the interval x > -2 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -2 will be zero.

The function is increasing when x < -2

$(- \infty,-2)$

The function is decreasing when x > -2

$(-2, \infty)$

Additional information

We can actually determine the intervals where the function is increasing and decreasing by differentiating the function.

The equation of this graph is:

$f(x)=-2x^2-8x-8$

$\implies f'(x)=-4x-8$

The function is increasing when $f'(x) > 0$

$\implies -4x-8 > 0$

$\implies -4x > 8$

$\implies x < -2$

The function is decreasing when $f'(x) < 0$

$\implies -4x-8 < 0$

$\implies -4x < 8$

$\implies x > -2$

This concurs with the observations made from the graph.

Question 8

This is a straight line graph. The gradient is negative, so:

The function is decreasing for all real values of x

$(- \infty,+ \infty)$

But if they want the interval for the grid only, it would be -4 ≤ x ≤ 1

$[-4,1]$

Question 9

If you draw a tangent to the curve in the interval x < -1 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve in the interval x > -1 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -1 will be zero.

The function is decreasing when x < -1

$(- \infty,-1)$

The function is increasing when x > -1

$(-1, \infty)$

5 0

1 year ago