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lakkis [162]
3 years ago
8

Sasha has 20 starburst in a bag 9 are yellow 6 are pink 4 are red and 2 are orange. Sasha will randomly select two starburst fro

m the bag with no replacement. What is the probability that she will select a yellow Starburst and then a red starburst?(Give your answer as a reduced fraction
Mathematics
1 answer:
Rudik [331]3 years ago
7 0

Answer:

9/95

Step-by-step explanation:

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

probability that she will select a yellow Starburst and then a red starburst = probability of picking a yellow starburst x probability of picking a red starburst

9/20 x 4/19 = 9/95

because there is no replacement, the number of balls after the yellow one is picked would reduce by 1

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3 years ago
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Answer:

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Step-by-step explanation:

The attachment shows a solution using a graphing calculator where the first equation is solved for z, and that expression is substituted into each of the other two equations. The solution to that system is (x, y) = (3, -2). Using these values in the expression for z, we find ...

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The solution is (x, y, z) = (3, -2, 4).

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Your graphing calculator and/or online tools can give you the reduced row echelon form of the augmented matrix representing the system:

  \left[\begin{array}{ccc|c}1&1&1&5\\-3&-4&4&15\\2&-1&-4&-8\end{array}\right]

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If you're solving by hand, you can do the substitution described above to eliminate z from one equation. You can eliminate z from another equation by adding the last two:

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  z = 5 -(3) -(-2) = 4

_____

<em>Additional comment</em>

If all that is needed is a solution, we prefer a graphical or matrix approach. These take about the same amount of time. Both require a little additional effort to determine exact values when the solutions are not integers.

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