Write the equation of the line that is parallel to y+2=5(x-1) and passes through the point (-1, 0)
1 answer:
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Answer:
(3, 1)
Step-by-step explanation:
plotting these points on a graph, while (3, 1) may look like it's on the line, it is the only point that would involve changing the slope of the line, so that point cannot be on the line.
Answer:
Option (1)
Step-by-step explanation:
The given triangle JKL is an equilateral triangle.
Therefore, all three sides of this triangle will be equal in measure.
Side JK = JL = KL = 48 units
Perpendicular LM drawn to the base JK bisects the base in two equal parts JM and MK.
By applying tangent rule in ΔJML,
tan(∠KJL) =
=
=
Since, Sin(K) =
Sin(60)° =
LM = 24√3
Now, tan(∠KJL) =
=
Therefore, Option (1) will be the answer.