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german
3 years ago
5

Slausonn can you pls answer this quesion pls i have 3 min left

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0
6 and 17
m+m+1=33
2m=32
m=16
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According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 in
Crazy boy [7]

Answer:

0.54035

Step-by-step explanation:

Given that :

Mean, m = 66 inches

Standard deviation, s = 2.5 inches

P(65 < X < 69)

P(X < 69) - P(X < 65)

((69 - 66) / 2.5) - ((65 - 66) / 2.5)

P(Z <(3/ 2.5)) - P(Z <(-1 / 2.5))

P(Z < 1.2) - P(Z < - 0.4)

0.88493 - 0.34458

= 0.54035

7 0
3 years ago
A population of beetles are growing according to a linear growth model. The initial population (week 0) is
klemol [59]

9514 1404 393

Answer:

  18 weeks

Step-by-step explanation:

We are given the (time, population) pairs (0, 5) and (7, 47). With these values, we can use the two-point form of the equation of a line to write the equation of the linear model.

  p = (p2 -p1)/(t2 -t1)(t -t1) +p1

  p = (47 -5)/(7 -0)(t -0) +5

  p = 6t +5 . . . . . the linear model matching the given points.

For p = 113, the time (number of weeks) is ...

  113 = 6t +5

  108 = 6t . . . . . . subtract 5

  18 = t . . . . . . . . . divide by 6

After 18 weeks, the beetle population will reach 113.

6 0
3 years ago
Solve for x <br>quick please need it done fast​
kifflom [539]

Answer:

x = 36

Step-by-step explanation:

EAB is a straight line so it equal 180

EAF + FAB = EAB

3x+2x = 180

Combine like terms

5x = 180

Divide each side by 5

5x/5 = 180/5

x = 36

3 0
4 years ago
Read 2 more answers
The median of Rae's data is 2.22 minutes, and the median of Doris' data is 2.14 minutes. The interquartile range for Rae is , an
JulsSmile [24]

Complete question :

Rae and Doris are training to swim a 200-meter freestyle race. The table lists their practice times during training camp.

Rae’s Times(minutes)-2.12, 2.01, 2.46, 2, 2.22, 2.31, 2.23

doris times(minutes)-2.32, 2.19, 2.26, 2.03, 2.11, 2.14, 2.07

The median of Raes data is(drop down box answers, 2,2.03,2.14,2.22)minutes,and the median of doris data is(drop down box answers, 2,2.03,2.14,2.22)minutes. The interquartile range for rae is(drop down box answers, 0.01,0.13,0.26,0.30), and the interquartile range for doris is(drop down box answers, 0.02,0.06,0.18,0.19). The two data sets overlap(drop down box answers,very little, a lot

Answer:

Rae's median = 2.22

Rae's IQR = 0.30

DORIS median = 2.14

Doris IQR = 0.19

Step-by-step explanation:

Given :

Rae's time :

Ordered data : 2, 2.01, 2.12, 2.22, 2.23, 2.31, 2.46

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.22

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.01

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.31

Interquartile range = Q3 - Q1 = 2.31 - 2.01 = 0.30

DORIS Data:

Ordered data: 2.03, 2.07, 2.11, 2.14, 2.19, 2.26, 2.32

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.14

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.07

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.26

Interquartile range = Q3 - Q1 = 2.26 - 2.07 = 0.19

6 0
3 years ago
tom had a very challenging fraction multiplycation problem to do, but his sister said it was really easy to do mentally. can you
krok68 [10]

Answer:

76/81×80

76=80/81

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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