The measures of the four angles of quadrilateral ABCD are 36°, 72°, 108° and 144°
<u>Explanation:</u>
A polygon has three or more sides.
Example:
Triangle has 3 sides
Square has 4 sides
Pentagon has 5 sides and so on.
27)
In a quadrilateral ABCD, the measure of ZA, ZB, ZC and ZD are the ratio 1 : 2 : 3 : 4
We know,
sum of all the interior angles of a quadrilateral is 360°
So,
x + 2x + 3x + 4x = 360°
10x = 360°
x = 36°
Thus, the measure of four angles would be:
x = 36°
2x = 2 X 36° = 72°
3x = 3 X 36° = 108°
4x = 4 X 36° = 144°
Therefore, the measures of the four angles of quadrilateral ABCD are 36°, 72°, 108° and 144°
Answer:
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Answer:
-a^2 + ab
Step-by-step explanation:
(a^2 - 2ab +b^2) + (2a^2 + 2ab + b2) = 3a^2 + 2b^2
(a^2 - b^2) + (a^2 + ab + 3b^2) = 2a^2 + 2b^2 + ab
subtract the first part from the second part:
(2a^2 + 2b^2 + ab) - (3a^2 + 2b^2) = -a^2 + ab
Start by dividing both sides by 2:
5x + 6 = 5x + 6
Simplify:
0 = 0
This indicates infinite solutions:
x = All real numbers.
Answer: Irrational
Explanation: bc it is