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Stella [2.4K]
3 years ago
5

PLEASE HELP ME VERY URGENT 20 points Part A: Factor 3x2a2 − 5xa2 − 2a2. Show your work. (4 points) Part B: Factor x2 − 10x + 25.

Show your work. (3 points) Part C: Factor x2 − 81. Show your work. (3 points)
Mathematics
1 answer:
irga5000 [103]3 years ago
3 0
PartA Factor 3x^2a^2 − 5xa^2 − 2a^2.
 3x^2a^2 − 5xa^2 − 2a^2= 
 a^2(3x^2 − 5x − 2)=
 a^2((x-2)*(x+(1/3))) Part B: Factor x^2 − 10x + 25. x^2 − 10x + 25.= (x-5)*(x-5) Part C: Factor x^2 − 81. Show your work. x^2 − 81=(x-9)*(x+9)

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Andrei [34K]

Answer:

I would say A

Step-by-step explanation:

8 0
3 years ago
Multi-Step Equation 2: Solve for x. Show your steps.<br> 6 - 5x + 2 = 3x - 12 + 2x
amm1812

Answer:

The answer is x = 8/5

Step-by-step explanation:

6 - 5x + 2 = 3x - 12 + 2x

4 - 5x = 5x - 12

4 = 10x - 12

16 = 10x

8/5 = x

4 0
2 years ago
Can you please show the working?
creativ13 [48]

The Price of Car A rounded to the Nearest £100 is £12400

The Price of Car B rounded to the Nearest £100 is £16800

The Price of Car C rounded to the Nearest £100 is £14600

Difference between the Rounded Price and Original Price of Car A :

⇒ (£12400 - £12380) = £20

Difference between the Rounded Price and Original Price of Car B :

⇒ (£16800 - £16760) = £40

Difference between the Rounded Price and Original Price of Car C :

⇒ (£14600 - £14580) = £20

From the above, We can Notice that :

The Price of Car B changes by the greatest amount.

4 0
3 years ago
The stopping distance for 10 cars traveling at 55 miles per hour is shown in the table above . What is the mean (average ) stopp
umka21 [38]

Answer:

50

Step-by-step explanation:

Add all of the numbers and divide by the number of columns. Ex.

48+49+50+51+51= 250

250÷5= 50

8 0
2 years ago
Solve the following ODE's: c) y* - 9y' + 18y = t^2
Nastasia [14]

Answer:

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = C_1e^{3t}+C_2e^{6t}

now calculating P.I.

P.I. = \frac{t^2}{D^2 - 9D +18}

P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

hence the complete solution

y = C.F. + P.I.

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

7 0
2 years ago
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