If the length is 2ft longer than it’s width
Let’s assume width as X and so the length will be X+2
Perimeter=40ft
Putting the values into a equation, we get,
X+2+X=40
=2X+2=40
=2X=38
=X=19
Therefore
Length =X+2=19+2
=21ft
Width=X=19ft
Area of rectangle =lxb
= 21x19
3992ft
HOPE IT WAS HELPFUL :)
Unsure of what you mean by "y1."
If you wish to solve this eqn for y, do this:
-5y = - 3x + 20,
-3x + 20
y = ---------------- = (3/5)x - 4 (answer)
-5
Answer:
Step-by-step explanation:
9
Solution A1 is correct hope it helpsss