Answer:
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%
Step-by-step explanation:
For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:
Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4
For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5
For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0
P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%
Answer:
16 meters basic math
Step-by-step explanation:
Answer:
Pete
Step-by-step explanation:
Given that:
Mandy's Estimate :
Number of spins , n = 20
Pete's Estimate:
Number of spins, n = 200
A good probability estimate is one which has narrow margin of error with a high degree of confidence. These two variables are affected by sample size.
A high sample size give a narrower margin of error and increases the confidence level probability
Based on the sample size used by each of Pete and Mandy, we can conclude that, Pete's probability estimate would be better due to its significantly higher sample size.
Answer:45,311
45,301+10=45,311
I hope this is good enough:
