Is a coin flip random? Why or why not, in your opinion?
2 answers:
You might be interested in
A = amount invested at 4%.
b = amount invested at 9%.
we know the total amount invested was $26500, thus a + b = 26500.
whatever% of anything is just (whatever/100) * anything.
how much is 4% of a? well, is just (4/100) * a, or 0.04a.
how much is 9% of b? well, is just (9/100) * b, or 0.09b.
we know the interest yielded for both amounts adds up to $1510, thus 0.04a + 0.09b = 1510.
how much was invested at 9%? well, b = 26500 - a.
b = amount invested at 9%.
we know the total amount invested was $26500, thus a + b = 26500.
whatever% of anything is just (whatever/100) * anything.
how much is 4% of a? well, is just (4/100) * a, or 0.04a.
how much is 9% of b? well, is just (9/100) * b, or 0.09b.
we know the interest yielded for both amounts adds up to $1510, thus 0.04a + 0.09b = 1510.
how much was invested at 9%? well, b = 26500 - a.
Answer:
136
Step-by-step explanation:
Well if you find the lateral area (the area of the rectangles on the sides) to get 112, so you just need to add that to the triangles and for those (they add up to 36) you can just use the formula for the area of a triangle, which is .
Hope this helps :)