Not clear on what you're asking buddy-boo
Answer:
Therefore the Dimensions of Rectangular field are
Step-by-step explanation:
Given:
Let the length of the Rectangular field be ' L '
and Width be 'W'
According to given Condition
Perimeter = 158 ft
To Find:
L = ?
W = ?
Solution:
Perimeter of Rectangle is given as
Substitute 'L' and Perimeter we get
Substitute 'W' in L we get
Therefore the Dimensions of Rectangular field are
Answer:
Step-by-step explanation:
Given Parallel lines Converse
a). ∠13 ≅ ∠17 a║c Corresponding angles
b). ∠4 ≅ ∠9 b║e Exterior alternate angles
c). m∠19 + m∠22 = 180° a║b Same side exterior angles
d). ∠8 ≅ ∠19 Vertical angles.
e). ∠10 ≅ ∠23 b║c Alternate angles
f). m∠14 + m∠17 = 180° a║c Same side Interior angles
Answer:
Step-by-step explanation:
(x²+4)²-11(x²+4)+24=0
put x²+4=y
y²-11y+24=0
y²-3y-8y+24=0
y(y-3)-8(y-3)=0
(y-3)(y-8)=0
y=3,8
so x²+4=3
x²=-1=i²
x=±i
or x²+4=8
x²=4
x=±2
Answer: x² = 4y -8
Step-by-step explanation: The equation of the set of points which are equidistant from a point and from a line is a parabola. In this case:
F ( 0 , 2 ) The parabola open upwards, so is of the form
p = 1
( x - h )² = 4*p* ( y - 2)
x² = 4 * ( y - 2 )
x² = 4y -8