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Nadusha1986 [10]
3 years ago
12

Giving brainlest if you solve 5-8

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0
Answer:
5: 1, 2, 4, 11, 22, 44
6: 1, 5, 25, 125
7: 1, 5, 17, 85
8: 1, 3, 13, 39
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Classify the following as discrete or continuous random variables.
Elena-2011 [213]

Answer:

A discrete variable is a variable that can only take some selected given values from a given set, like x ∈ {x₁, x₂, ..., xₙ}

While a continuous variable can take any value in the range, like x ∈ {x₁, xₙ}.

1)  The weight of bags of apples, with 10 apples in each bag.

Here the weight depends on the number of apples in the bag, and we can have only whole numbers of apples in the bag, so this is clearly a discrete variable.

2) The number of times required for a modem to dial an internet provider before connecting.

Same as before, here we can have only a whole number of attempts, so this set is discrete.

3) Out of 10 times connecting to an internet provider, the average number of attempts necessary before connecting.

Here we will have an average of 10 integer numbers:

M = \frac{x_1 + x_2 + ... + x_{10}}{10}

so here we have a kinda dense set of possible values, so we can think of this as a continuous variable.

4)  A pair of dice is rolled, and the sum to appear on the dice is recorded.

Here the possible values are whole numbers again, so we can not have values like 3.5, so again, this is a discrete variable.

8 0
3 years ago
Help me on this algebra homework
Makovka662 [10]
X = 
2. -7
7. 15
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4 0
3 years ago
According to the U.S. Bureau of Labor Statistics, 20% of all people 16 years of age or older do volunteer work. In this age grou
Murljashka [212]

Answer:

1. P(X≥35) = 0.0183

2. P(X≤21) = 0.0183

3. P(0.18<p<0.25) = 0.7915

Step-by-step explanation:

We have the proportion for women: pw=0.22, and the proportion for men: pm=0.19.

1. We have a sample of 140 woman and we have to calculate the probability of getting 35 or more who do volunteer work.

This is equivalent to a proportion of

p=X/n=35/140=0.25

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.22*0.78}{300}}\\\\\\ \sigma_p=\sqrt{0.0006}=0.0239

We calculate the z-score as:

z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.25-0.22}{0.0239}=\dfrac{0.03}{0.0239}=0.8198

Then, the probability of having 35 women or more who do volunteer work in this sample of 140 women is:

P(X>35)=P(p>0.25)=P(z>2.0906)=0.0183

2. We have to calculate the probability of having 21 or fewer women in the group who do volunteer work.

The proportion is now:

p=X/n=21/140=0.15

We can calculate then the z-score as:

z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.15-0.2}{0.0239}=\dfrac{-0.05}{0.0239}=-2.0906

Then, the probability of having 21 women or less who do volunteer work in this sample of 140 women is:

P(X

3. For the sample with men and women, we use the proportion for both, which is π=0.2.

The sample size is n=300.

Then, the standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.2*0.8}{300}}\\\\\\ \sigma_p=\sqrt{0.0005}=0.0231

We can calculate the z-scores for p1=0.18 and p2=0.25:

z_1=\dfrac{p_1-\pi}{\sigma_p}=\dfrac{0.18-0.2}{0.0231}=\dfrac{-0.02}{0.0231}=-0.8660\\\\\\z_2=\dfrac{p_2-\pi}{\sigma_p}=\dfrac{0.25-0.2}{0.0231}=\dfrac{0.05}{0.0231}=2.1651

We can now calculate the probabilty of having a proportion within 0.18 and 0.25 as:

P=P(0.18

5 0
3 years ago
Pre-Calc<br> It's timed, pls help
Bezzdna [24]

Answer:

I think it's B.

Hopefully this helps, sorry if i doesn't.

(Also i saw your Technoblade pfp, very nice)

6 0
3 years ago
A paper cup in the shape of a cone has a radius of 6 cm and is 5 cm high. What is the volume of the cup ?
Vladimir79 [104]
The volume of the cone = 188.5 cm3

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2 years ago
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